Question

Which statement accurately describes how to reflect point A (−2, 1) over the x‐axis? Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line, find a new point on the other side of the x-axis that is equidistant from the x-axis. Construct a line from A parallel to the x-axis, determine the distance from A to the x-axis along this parallel line, find a new point on the other side of the x-axis that is equidistant from the x-axis. Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis. To reflect A over the x-axis you must find the intersection of a line perpendicular to the x-axis through point A, that will act as a bisector. This option is incorrect.#^ Construct a line from A parallel to the y-axis, determine the distance from A to the y-axis along this parallel line, find a new point on the other side of the y-axis that is equidistant from the y-axis.

Answer 1

Answer:

Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line, find a new point on the other side of the x-axis that is equidistant from the x-axis

Step-by-step explanation:

we know that

The rule of the reflection of a point across the x-axis is equal to

(x,y) -----> (x,-y)

That means ----> The reflected point will be located equidistant from the x-axis

so

Construct a line from A perpendicular to the x-axis

Determine the distance from A to the x-axis along this perpendicular line

Find a new point on the other side of the x-axis that is equidistant from the x-axis

therefore

A(-2,1) --------> A'(-2,-1)

The reflection point is A'

The distance of point A to the x-axis is equal to 1 unit

The distance from point A' to the x-axis is also 1 unit