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3 years ago

Factor by grouping.

2 answers:

6 0

1.)b
2.)c
3.)a
1.)work
(3dt-21d)+(35-5t)
=3d(t-7)+5 (7-t)
=3d(t-7)-5(-7+t)
=3d(t-7)-5(t-7)
=(t-7)(3d-5)

2.) work
vp+12v+8p+96
=(vp+12)+(8p+96)
=v(p+12)+8(p+12)
=(p+12)(v+8)

hram777 [196]3 years ago

4 0

The correct answers are A C and B

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Please solve and explain how. Photo attached

geniusboy [140]

Answer:

Step-by-step explanation:

$\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}$

multiply by $\frac{k^2-2k}{1}$ on each side

$2=k^2-2k-1$

add 1 on both sides $3=k^2-2k$

make it equal 0

$0=k^2-2k-3$

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$(k-3)(k+1)$

answer is 3 and -1

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2 years ago

Tell whether the ordered pair (- 3, 0) is a solution of the given system. - 2x + 2y >= 4an y >= 2x - 6

alukav5142 [94]

Answer:

The ordered pair is a solution.

Step-by-step explanation:

Plug x = -3 and y = 0 into the 2 inequalities and see if they fit:

-2x + 2y >= 4

-2(-3) + 2(0) = 6 which is > 4 so this one fits.

y>= 2x - 6

0 >= 2*-3) - 6 = -12 which also fits.

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3 years ago

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Find the value of f(4) for the function. f(a) = 2(a + 4)-4

mixer [17]

Step-by-step explanation:

4a=2a+4

C.L.T

4a-2a=4

2a=4

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2 years ago

You are a volunteer at a physical therapy clinic. a set of stairs you use to help patients is shown with it's dimensions. What i

vazorg [7]

The volume formula is area of base×height. In this case, we are working with rectangles, so the formula is l×w×h. We have to find the volume of each block and add them together. Top rectangle: 12×30×4=1440. Middle rectangle: 30×36×4=4320. Bottom rectangle: 30×60×4=7200. 7200+4320+1440=12960 inches squared.

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3 years ago

If the mean heights of three groups of students consisting of 20,16 and 14 students are 167m, 150m and 1.40m respectively find t

Aleonysh [2.5K]

Answer:

1.54 m

Step-by-step explanation:

Given information:

Three groups of students

20 students with a height of 1.67 m
16 students with a height of 1.50 m
14 students with a height of 1.40 m

⇒ Total number of students = 20 + 16 + 14 = 50

To find the mean height of all the students, divide the sum of all the students' heights by the total number of students:

$\begin{aligned}\implies \sf mean\:height & =\dfrac{(20 \times 1.67)+(16 \times 1.50)+(14 \times 1.40)}{50}\\\\ & = \dfrac{33.4+24+19.6}{50}\\\\ & = \dfrac{77}{50}\\\\ & = 1.54\:\: \sf m\end{aligned}$

Therefore, the mean height of all the students is 1.54 m

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1 year ago

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