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3 years ago

6

To newtons second law of motion the force acting on an object and very directly with the objects acceleration suppose that I for

ce of

1 answer:

MArishka [77]3 years ago

7 0

For example fill ur bathtub full of water. then lay down in the tub the water leaving the tub is the force acting back.

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C is the answer. Hope you get a good grade

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3 years ago

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3 years ago

Simplify ( √ 5)(^3 √ 5) the answer will be a wholenumber and a fraction

arlik [135]

Answer:

$\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}$

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The rules of exponents apply, even when they are fractional exponents:

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3 years ago

What are the coordinates of the midpoint of GH with endpoints (-2,5) and<br> H(4,1)?

kozerog [31]

Answer:

(1, 3)

Step-by-step explanation:

Given coordinates of 2 endpoints, G(-2, 5) and H(4, 1), midpoint of AB is calculated as shown below:

Midpoint (M) of GH, for G(-2, 5) and H(4, 1) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $G(-2, 5) = (x_1, y_1)$

$H(4, 1) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 4}{2}, \frac{5 + 1}{2})$

$M(\frac{2}{2}, \frac{6}{2})$

$M(1, 3)$

Coordinates of the midpoint of GH = (1, 3).

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3 years ago

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Gnom [1K]

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