All categories

3 years ago

7^23.14a=1077.02 What is a?

Mathematics

2 answers:

SashulF [63]3 years ago

6 0

$7^{2} * 3.14 * a =1077.02
$
$49 * 3.14 * a =1077.02$
$153.86 * a =1077.02$
$153.86 / 1077.02 = 7$
$a=7$

eimsori [14]3 years ago

3 0

A =7

7^2*3.14*7 sorry I did the equation wrong at first

You might be interested in

May you please help me??

mart [117]

Answer:

.....the answer is 1400

3 0

3 years ago

Read 2 more answers

Find the volume of a half sphere with a radius of 10

Ugo [173]

The volume of a sphere is calculated like so:
v = 4*pi*r^3/3
so half sphere will have half that volume:
v = (4*pi*r^3/3)(1/2)
v = 4*pi*r^3/6
plug in the data:
v = 4*pi*(10)^3/6
v = 2094.4
that is the volume of the half sphere

7 0

3 years ago

A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 respon

Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14% chose chocolate pie, and the margin of error was given as plus or minus ±3 percentage points.

The pivotal quantity for the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who chose chocolate pie = 14%

n = sample of adults = 500

p = true proportion

Now, the 99% confidence interval for p = $\hat p \pm Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

Here, $\alpha$ = 1% so $(\frac{\alpha}{2})$ = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.03 for 99% interval.

So, 99% confidence interval for p = $0.14 \pm2.5758 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

= [0.14 - 0.03 , 0.14 + 0.03]

= [0.11 , 0.17]

Similarly, 80% confidence interval for p = $0.14 \pm 1.2816 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

Here, $\alpha$ = 20% so $(\frac{\alpha}{2})$ = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.02 for 80% interval.

So, 80% confidence interval for p = [0.14 - 0.02 , 0.14 + 0.02]

= [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0

3 years ago

A Nevada roulette wheel had 38 pockets, labeled as 0 00 1 2 3 ... 35 36. One bet is single number. If you bet $1 on a number (an

slavikrds [6]

Answer:

-0.0526

Step-by-step explanation:

Let X be the random variable denoting the net gain(in dollars) for a single trial(one bet).

Assuming that each number in the wheel is equally likely, probability of the outcome being a victory is $\frac{1}{38}$ and probability of failure is $\frac{37}{38}$ . For a win, X takes value 35 and for a loss X takes value -1. So the model is,