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4 years ago

How to do #9.........

Mathematics

1 answer:

Serhud [2]4 years ago

5 0

4x and 2x line along a straight line, their sum then must be 180° so

6x=180

x=30

So the angles in there are:

3(30)-5=85°

2(30)=60°

4(30)=120°

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Find the first four terms of the sequence<br> An=2a n-1,where a1=3

yKpoI14uk [10]

The first four terms of the sequence are 3 , 6 , 12 , 24

Step-by-step explanation:

We need to find the first four terms of the sequence $a_{n}=2a_{n-1}$

where $a_{1}=3$ to find them do that

Substitute n by 2 in the rule to find $a_{2}$
Substitute n by 3 in the rule to find $a_{3}$
Substitute n by 4 in the rule to find $a_{4}$

∵ $a_{n}=2a_{n-1}$

- Substitute n by 2 to find the 2nd term

∴ $a_{2}=2a_{2-1}$

∴ $a_{2}=2a_{1}$

∵ $a_{1}=3$

∴ $a_{2}=2(3)$

∴ $a_{2}=6$

- Substitute n by 3 to find the 3rd term

∴ $a_{3}=2a_{3-1}$

∴ $a_{3}=2a_{2}$

∵ $a_{2}=6$

∴ $a_{3}=2(6)$

∴ $a_{3}=12$

- Substitute n by 4 to find the 4th term

∴ $a_{4}=2a_{4-1}$

∴ $a_{4}=2a_{3}$

∵ $a_{3}=12$

∴ $a_{4}=2(12)$

∴ $a_{4}=24$

The first four terms of the sequence are 3 , 6 , 12 , 24

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

#LearnwithBrainly

3 0

3 years ago

Can you use the Pythagorean theorem to relate thethree sides of this triangle?

irina1246 [14]

Answer:

You can use the Pythagorean Theorem to find the length of the hypotenuse of a right triangle if you know the length of the triangle's other two sides, called the legs. You can use the Pythagorean Theorem to find a value for the length of c, the hypotenuse.

6 0

3 years ago

If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?

Ierofanga [76]

$GEOMETRIC \: \: PROGRESSIONS \\ \\ \\\\Let \: the \: G.P. \: be \: \: A \: , \: Ar \: , \: A {r}^{2} \: ... \\ \\ Where \:first \: term \: is \: \: A \: \: \\ and \: common \: ratio \: is \: \: R \\ \\ Let \: An \: denotes \: the \: \: nth \: term \: of \: \\ the \: given \: Geometric \: Progression \: \\ \\ It \: is \: given \: - \\ \\ A1 \: = \: 72 \\ \\ A2 \: = \: 216 \\ \\ Common \: ratio \: = \: \frac{A2}{A1} = \frac{216}{72} \\ \\ R = 3 \\ \\ A \: = \: 72 \\ \\ A3 \: = \: A {r}^{2} = 72 \times 3 \times 3 \\ \\ \\ Hence \: , \: A3 \: = \: 648 \: \: \: \: \: \: \: Ans.$