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Reil [10]
3 years ago
7

Please someone help with this math problem!!!!

Mathematics
1 answer:
zysi [14]3 years ago
7 0
So it would be that you are very beautiful!
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If p(x) = x2 – l and q ( x ) = 5x – 5 which expression is equivalent to (p-q) (x)?
Natali [406]

Answer:

x^2 - 5x + 4.

Step-by-step explanation:

(p - q)(x) =  x^2 - 1 - (5x - 5)

= x^2 - 5x - 1 + 5

= x^2 - 5x + 4.

7 0
3 years ago
A number divided by 7 is 9
klemol [59]
A number divided by 7 is 9: \frac{x}{7} =9
Multiply both sides by 7 to get the answer so it'll be: \frac{x}{7} (7)=9(7)

x = 63
4 0
3 years ago
Read 2 more answers
LCM of 8 and 9 using lists.
muminat
8,16,24,32,40,48,56,65,73,81,88.....
9,18,27,36,45,54,63,72,81,90....

since 81 is the smallest number in both lists, it is the LCM
4 0
3 years ago
Rewrite the formula to find the width of the base of the prism if the volume, length of the base, and height of the prism are al
sergeinik [125]
You can maybe enter your question on google if you dont get any answers
8 0
3 years ago
Select the correct answer from each drop-down menu.
Oksi-84 [34.3K]

Answer:

we \: have \: ohms \: law \: h =  {i}^{2} rt \\  \frac{h}{t}  =  {i}^{2} rt \div t = p \\  p =  {i}^{2} r....(1) \\ we \: have \: v = ir \\ i =  \frac{v}{r} .....(2) \\ put \: (2) \: in \: (1) \\ then \: p =  { (\frac{v}{r}) }^{2} r \\ p =  \frac{ {v}^{2} }{r}  \\ v =  \sqrt{pr}  =  {(pr)}^{ \frac{1}{2} }  \\ 2) \\ here \: r = 32 \: and \: p = .5 \\ then \: v =  \sqrt{32 \times .5}  \\  =  \sqrt{16}  = 4volt \\ thank \: you

6 0
3 years ago
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