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kykrilka [37]
3 years ago
5

What are the y and x intercepts for -5x-4y=10

Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

x-intercept(s) = (-2,0)

y-intercept(s) = (0, - 5/2)

Step-by-step explanation:

the x-intercept, substitute in  0  for  y  and solve for  x . To find the y-intercept, substitute in  0  for  x  and solve for  y .

x-intercept(s) = (-2,0)

y-intercept(s) = (0, - 5/2)

statuscvo [17]3 years ago
6 0

Answer:

x=-2,0 and y=0,-5/2

Step-by-step explanation:

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Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

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where, \bar X = sample mean weight = 31.8 ounces

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             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

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The value of t test statistics is -1.614.

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Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

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