Question

What is the distance between (-4, 8) and (12, 8) on the coordinate plane? A 16 units B 8 units C 0 units D 4 units

Answer 1

Answer:

16 units

Step-by-step explanation:

We need to find the distance between (-4, 8) and (12, 8) on the coordinate plane.

We know that the distance between two points on the coordinate plane is given by :

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Put x₁ = -4, x₂ = 12, y₁ = 8 and y₂ = 8

So,

$D=\sqrt{(12-(-4))^2+(8-8)^2}\\\\=16\ units$

So, the distance between the two points is equal to 16 units.