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bekas [8.4K]
2 years ago
10

What is the distance between (-4, 8) and (12, 8) on the coordinate plane? A 16 units B 8 units C 0 units D 4 units

Mathematics
1 answer:
Papessa [141]2 years ago
5 0

Answer:

16 units

Step-by-step explanation:

We need to find the distance between (-4, 8) and (12, 8) on the coordinate plane.

We know that the distance between two points on the coordinate plane is given by :

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Put x₁ = -4, x₂ = 12, y₁ = 8 and y₂ = 8

So,

D=\sqrt{(12-(-4))^2+(8-8)^2}\\\\=16\ units

So, the distance between the two points is equal to 16 units.

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ehidna [41]

Answer:

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Step-by-step explanation:

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The answer is  (x - 8)^2 + (y - 0)^2 = 3

or (x - 8)^2 + y^2 = 3.

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3 years ago
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castortr0y [4]
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8 0
3 years ago
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Answer:

Step-by-step explanation:

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From the given right angle triangle,

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