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zhuklara [117]
3 years ago
7

Dos masas están conectadas por una cuerda ligera que pasa por una polea sin rozamiento. Determine la aceleración de las masas y

la tensión de la cuerda si m Kg A  20 , m Kg B  50 y  0.20  K A Y B
Physics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:A

Explanation:

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Do you like genetic engineering explain even if there is no answer box still answer in the commets
liubo4ka [24]

Answer:

yes it is so awesome

Explanation:

4 0
2 years ago
Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the
saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

R=\alpha \frac{l}{s}

Were:

R is resistance

\alpha is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area (s=\pi r^{2}).

So if the lenght and radius are doubled, the equation goes as follows:

R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }

So finally because the circular area is a square function, the resulting equation is half of the one before.

7 0
3 years ago
Answer these two questions please
Grace [21]
1.The answer is True
2.The answer is False
8 0
3 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
aivan3 [116]
A. a<span> = 1.3 m/s^2</span><span>; </span>FN<span> = 63.1 N</span>
4 0
2 years ago
Read 2 more answers
If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What
Pavel [41]

Answer: 1.54m^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 1 atm

P_2 = final pressure of gas = 2.67 atm

V_1 = initial volume of gas = 3.61m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas at STP = 0^oC=273+0=273K

T_2 = final temperature of gas = 37.9^oC=273+37.9=310.9K

Now put all the given values in the above equation, we get:

\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}

V_2=1.54m^3

Thus the final volume will be 1.54m^3

7 0
3 years ago
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