Diagram D. shows the sound waves generated by a siren
that is moving with constant speed to the left.
A sound wave is the sample of disturbance caused by the movement of strength journeying thru a medium because it propagates far away from the supply of the sound. Sound waves are created by using object vibrations and bring strain waves, for example, a ringing cellular phone.
Sound waves fall into three classes: longitudinal waves, mechanical waves, and strain waves. keep studying to find out what qualifies them as such. Longitudinal Sound Waves A longitudinal wave is a wave wherein the movement of the medium's debris is parallel to the course of the energy transport. Sound propagates via air or different mediums as a longitudinal wave, in which the mechanical vibration constituting the wave occurs along the direction of propagation of the wave.
Learn more about sound waves here:-brainly.com/question/1199084
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Answer
Pressure, P = 1 atm
air density, ρ = 1.3 kg/m³
a) height of the atmosphere when the density is constant
Pressure at sea level = 1 atm = 101300 Pa
we know
P = ρ g h


h = 7951.33 m
height of the atmosphere will be equal to 7951.33 m
b) when air density decreased linearly to zero.
at x = 0 air density = 0
at x= h ρ_l = ρ_sl
assuming density is zero at x - distance

now, Pressure at depth x


integrating both side


now,


h = 15902.67 m
height of the atmosphere is equal to 15902.67 m.
Answer:
To obtain the power, we first need to find the work made by the force.
1) To calculate the work, we need the next equation:

So the force is given by the problem so our mission is to find 'dx' in terms of 't'
2) we know that:

So we have:

Then:

3) Finally, we replace everything:

After some calculation, we have as a result that the work is:
161.9638 J.
4) To calculate the power we need the next equation:

So
P = 161.9638/4.7 = 34.46 W
I believe the correct answer is B.<span>positively charged hair.</span>
Yes, if the temperature increases, than that means the particles are moving faster. Temperature is the measure of movement of particles in an object or substance.
By thermal energy, you mean adding heat correct....? I'm not very good at this sort of thing, but I gave you what I have..