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DanielleElmas [232]
3 years ago
5

Rain falls vertically downward with the velocity of 3.3 m/s. a boy moves at a speed of 5 m/s east in a bicycle with an umbrella.

what is the velocity of the rain with respect to the boy?

Physics
1 answer:
qaws [65]3 years ago
8 0
Refer to the diagram shown below.

The velocity of the rain relative to the boy is given by
\vec{V}_{r/b} = \vec{V}_{r} - \vec{V}_{b}
in a vectorial sense as shown in the figure.

Given:
Vr = 3.3 m/s
Vb = 5 m/s

Use the Pythagorean to obtain
Vr/b = √(3.3² + 5²) = 6 m/s

The angle that Vr/b makes with due east is
θ = tan⁻¹ (3.3/5) = 33.4°
Answer:
The velocity of the rain with respect to the boy is 6 m/s.
The direction of the rain is 33.4° north of due east.

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Let the displacement function of a particle is x(t)=(20t^2-15t+200). Find the total displacement, instantaneous velocity and ins
irga5000 [103]

Answer:

A.) 39.5 m

B.) 0

C.) 60m/s^2

Explanation:

Given that a displacement function of a particle is x(t)=(20t^2-15t+200).

To Find the total displacement,

Reduce everything by dividing them by 5

X(t) = 4t^2 - 3t + 40 ...... (1)

For instantaneous velocity, differentiate x(t). That is,

dy/dt = 60t - 15 ...... (2)

But dy/dt = velocity.

If dy/dt = 0, then

60t - 15 = 0

60t = 15

t = 15/60

t = 0.25s

Substitutes t in equation (1)

Total displacement will be

X(t) = 4(0.25)^2 - 3(0.25) + 40

X(t) = 0.25 - 0.75 + 40

Total displacement = 39.5 m

To calculate instantaneous velocity, substitute t into equation (2)

V = 60 (0.25) - 15

V = 0.

and to find instantaneous acceleration, differentiate dv/dt

dv/dt = 60

Therefore, acceleration = 60 m/s^2

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2 years ago
Anyone please help me with this question ASAP
Katyanochek1 [597]

Answer:

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Explanation:

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3 years ago
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the space shuttle used three parachutes to land in the image at the start of the project. Why did the space shuttle engineers us
iragen [17]

Answer:

Sep 9, 2008 - Image above: In the Parachute Refurbishment Facility at NASA's ... His parachute, when opened, had a canopy that resembled a huge umbrella. ... Space Center used mainly to process space shuttle parachutes, United Space ... Hillebrandt also is lead engineer for the Constellation Program's Ares 1 rocket ...

Explanation:

Sep 9, 2008 - Image above: In the Parachute Refurbishment Facility at NASA's ... His parachute, when opened, had a canopy that resembled a huge umbrella. ... Space Center used mainly to process space shuttle parachutes, United Space ... Hillebrandt also is lead engineer for the Constellation Program's Ares 1 rocket ...

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2 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th
ipn [44]

Answer:

a) F_{fric} = 692 N

b) F_{applied} = 932 N

Explanation:

a)

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object  in all directions.

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

F_{applied} = 800 N

Mass = m = 90 kg

acceleration = a = 1.2 m/s²

F_{fric} = ?

800 - F_{fric} = (90)(1.2)

F_{fric} = 692 N

b)

According to newton's second law of motion,

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

If we assume the same friction and acceleration between player's feet and ground as calculated in part a

F_{fric} = 692 N

acceleration = a = 1.2 m/s²

We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.

Mass = M = m₁ + m₂ = 110 kg + 90 kg

= 200 kg

F_{applied} = ?

F_{applied} - 692 N = (200)(1.2)

F_{applied} = 692 + 240

F_{applied} = 932 N

7 0
3 years ago
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