Rain falls vertically downward with the velocity of 3.3 m/s. a boy moves at a speed of 5 m/s east in a bicycle with an umbrella.
what is the velocity of the rain with respect to the boy?
1 answer:
Refer to the diagram shown below.
The velocity of the rain relative to the boy is given by
in a vectorial sense as shown in the figure.
Given:
Vr = 3.3 m/s
Vb = 5 m/s
Use the Pythagorean to obtain
Vr/b = √(3.3² + 5²) = 6 m/s
The angle that Vr/b makes with due east is
θ = tan⁻¹ (3.3/5) = 33.4°
Answer:
The velocity of the rain with respect to the boy is 6 m/s.
The direction of the rain is 33.4° north of due east.
The velocity of the rain relative to the boy is given by
in a vectorial sense as shown in the figure.
Given:
Vr = 3.3 m/s
Vb = 5 m/s
Use the Pythagorean to obtain
Vr/b = √(3.3² + 5²) = 6 m/s
The angle that Vr/b makes with due east is
θ = tan⁻¹ (3.3/5) = 33.4°
Answer:
The velocity of the rain with respect to the boy is 6 m/s.
The direction of the rain is 33.4° north of due east.
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Explanation:
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Terminal voltage = 3.200 V
Internal resistance
(a). We need to calculate the current
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Where, E = emf
R = resistance
r = internal resistance
Put the value into the formula
(b). We need to calculate the terminal voltage
Using formula of terminal voltage
Where, V = terminal voltage
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r = internal resistance
Put the value into the formula
(c). We need to calculate the ratio of the terminal voltage of voltmeter equal to emf
Hence, This is the required solution.