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3 years ago

David is investigating the properties of soil using the sample shown.

1 answer:

7 0

Although the sample is not shown in this question, we can conclude that it would be reasonably easy for David to provide evidence of the color, consistency, temperature, and texture of the soil.

<h3 />

<h3>What are these properties an example of?</h3>

These are all examples of the physical properties of a sample. Since we cannot see the sample that David is using, it would be safest to assume that he would have no trouble providing evidence as to the physical properties of the soil, the:

Color
Consistency
Temperature
Texture

are all examples of this.

Therefore, we can confirm that David can provide evidence of the color, consistency, temperature, and texture of the soil.

To learn more about physical properties visit:

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A ball is projected horizontally from a table 1.0 m high and hits the ground after falling from a time t=0.45s. If the ball trav

photoshop1234 [79]

The initial velocity is $6.7 m/s$

Explanation:

The motion of the ball is a projectile motion, therefore it consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

In this problem, we just need to analyze the horizontal motion: the horizontal velocity is constant, therefore the horizontal distance travelled is given by

$x=v_x t$

where

$v_x$ is the horizontal velocity

t is the time of flight

Here we have:

t = 0.45 s

x = 3.0 m

And so solving for $v_x$ , we find

$v_x = \frac{3.0}{0.45}=6.7 m/s$

And since the ball was initially projected horizontally, this is also the initial velocity.

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3 years ago

A cell phone plan includes unlimited phone calls, texts, and data. There is an initial activation fee

Monica [59]

Answer:

90 months

Explanation:

1. 290 - 20 = 270

2. 270/3 = 90

4 0

3 years ago

Read 2 more answers

Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the force of repulsion

Luba_88 [7]

$first \: positive \: charge = q1 = 20$

$1micro \: = {1}^{ - 6}$

$1q = 20 \times 10 {}^{ - 6}$

$second \: charge = q2 = 100 \times 10 {}^{ - 6}$

$formula = f = \frac{k \times q1 × q2}{d {}^{2} }$

remember

$k = 9 \times {10}^{9}$

change distance 150cm to 1.5m

putting values

f = $\frac{9 \times 10 {}^{9} \times 20 \times 10 {}^{ - 6} \times 100 \times {10}^{ - 6} }{1.5 {}^{2} }$

<h2 /><h3>answer </h3><h3><u>8</u><u>N</u></h3>

4 0

3 years ago

Jim rode at an average speed of 12mph in 2 hours the he walked at an average of speed of 3 mph 0.5 hours what was the total dist

mrs_skeptik [129]

Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

6 0

4 years ago

A 5.0-kg object is pulled along a horizontal surface at a constant speed by a 15-n force acting 20° above the horizontal. How mu

puteri [66]

Answer:

84.6 J

Explanation:

The work done by the force is given by

$W=Fd cos \theta$