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Likurg_2 [28]
3 years ago
15

which graph represnts a line with a slope ot -2/3 and a y-intercept equal to that of the line y=2/3x-2?

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0
The graph will be as shown in attached figure

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You have 236 feet of fence to work with. What the maximum area that can be fenced in?
alexandr1967 [171]

Answer:

The maximum area is 4434.5 feet square.

Step-by-step explanation:

The fence maximum area it need to be fenced have to be shaped as circle. First we need to find radius of the circle:

2*\pi *r=236\\r=37.58

Maximum area will be fenced is:

S=\pi *r^{2} =3.14*37.58^2=4434.5

4 0
3 years ago
i have two points, (3,5) and (2,18) i need to find the exponential equation using these points. how do i do this?
Flauer [41]

Answer:  y = (5832/25)*(5/18)^x

==========================================================

Explanation:

Any general exponential function is of the form

y = a*b^x

Plug in (x,y) = (3,5) and we get

y = a*b^x

5 = a*b^3

If you plug in (x,y) = (2,18), then we'll get this other equation

18 = a*b^2

-------------------

So we have this system of equations

\begin{cases}5 = ab^3\\18 = ab^2\end{cases}

From here, we divide the two equations straight down. The left hand sides divide to 5/18. The right hand sides divide to (ab^3)/(ab^2) which simplifies to b. The 'a' terms cancel and we subtract the exponents for the b terms.

Overall, we end up with b = 5/18

---------------------

Use that value of b to find 'a'

18 = a*b^2

18 = a*(5/18)^2

18 = a*(25/324)

18*(324/25) = a

a = 5832/25

You could use the other equation as well to find 'a'

----------------------

Therefore, the equation in y = a*b^x form is y = (5832/25)*(5/18)^x

To verify this, plugging in x = 3 should lead to y = 5. Similarly, plugging in x = 2 should lead to y = 18.

5 0
3 years ago
Please help meeee !!!!!!!!! Will mark Brianliest correct answer !!!!!!!!!!!!!!!!!!
Andru [333]

Answer:

it is 7 inches tall - pythagorean theorem

Step-by-step explanation:

6 0
3 years ago
Need help with this please
ryzh [129]

Answer:

-2/5

Step-by-step explanation:

Exactly the opposite of the sign, opposite of + is negative (-)

8 0
3 years ago
i need a box with a square base and an open top that cna hold 500 in^3. what is the least amount of material i can use to build
exis [7]

Answer:

M(x)  =  452,56 in

Step-by-step explanation:

The volume of the open box is  500 in³

V = Area of the base times height

V(b) =  x² * h               where x is the side of the square and h the heigh

Then     500 =  x²*h

Total material to use is: material of the base + material of 4 sides

material of the base is  x²

material of one side is x*h  we have 4 sides then  4*x*h

Total material M(b)

M(b)  =  x²  +  4*x*h

And    as    h  =  500/ x²

M(x)  =  x²  +  4* x* 500/x²

M(x)  =  x²  +  2000/x

Tacking derivatives on both sides of the equation

M´(x)  =  2*x   - 200/x²

M´(x)  =  0         2*x  -  200/x²  = 0

x³ -  100  =  0

x³   =  100

x   =  4,64 in

And By substitution     h  =  500/x²

h  =  500/(4,64)²           h  =  23,22  in

How do we know that x = 4,64 make V(x) minimum

we get the second derivative

M´´(x)  =  2  +  200*2x/ x⁴    =  2  +  400/x³

M´´(x) is always positive

M´´(x) > 0     then M(x) has a minimum for  x= 4,64 in

The least amount of material is:

M(x)  =  x²    +    2000/x

M(x)  =  (4,64)²  *  2000/4,64

M(x)  = 21,53  +  431,03

M(x)  =  452,56 in

8 0
3 years ago
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