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3 years ago

Please answer these 2 questions

Mathematics

1 answer:

Mamont248 [21]3 years ago

3 0

Answer:

FINE ITS A AND B

Step-by-step explanation:

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Find a unit vector in the direction of the vector left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 8 2nd Row 1st Col

MrRissso [65]

Answer:

$\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]$

Step-by-step explanation:

We are required to find a unit vector in the direction of:

$\left[\begin{array}{c}-8\\7\\2\end{array}\right]$

Unit Vector, $\hat{a}=\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}$

The Modulus of $\overrightarrow{a}$ = $\sqrt{(-8)^2+7^2+(-2)^2}=\sqrt{117}$

Therefore, the unit vector of the matrix is given as:

$\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]$

5 0

4 years ago

Which statement is false:

Nat2105 [25]

9514 1404 393

Answer:

C. Equivalent ratios are ratios that name a different, unequal ratio.

Step-by-step explanation:

Statement C simply makes no sense. It cannot be considered to be true.

Statement D seems to be missing a word: ... the rate is called a unit <em>rate</em>.

7 0

3 years ago

Can you put this in order -4, 5/8, 3, and -2.9

Katyanochek1 [597]

-2.9,-4,5/8,3 the negatives go first

7 0

4 years ago

This is easy but i need help on it

Murljashka [212]

A is a function

To represent a function each value from the input (x ) can only map to exactly one value in the output (y)

In B

x = 3 → y = 10/ 30 ← 2 values of y

In C

x = - 5 → y = 2/ 3 ← 2 values of y

x = - 10 → y = 4/ 5 ← 2 values of y

In D

x = 20 → y = 25/ 35 ← 2 values of y

A is the only table where each value of x maps to exactly one value in y

3 0

3 years ago

Read 2 more answers

Find sin θ and cos θ if tan θ= 1/4 and sin 0>0.

Serga [27]

Answer:

$\displaystyle \sin(\theta)= \frac{\sqrt{17}}{17}$

$\displaystyle \cos(\theta)= \frac{4 \sqrt {17} }{ 17 }$

Step-by-step explanation:

We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.

First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.

Recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

$h=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}$

So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.

Then it follows that:

$\displaystyle \sin(\theta)=\frac{1}{\sqrt{17}} = \frac{\sqrt{17}}{17}$

And that:

$\displaystyle \cos(\theta)= \frac{4}{\sqrt{17}} = \frac{4 \sqrt {17} }{ 17 }$

5 0

3 years ago