Answer:
ΔU = -6.2 × 10⁴ J
Explanation:
The system absorbs 965 J of heat, that is, q = 965 J.
The work (w) can be calculated using the following expression.
w = -P . ΔV
where,
P is the external pressure
ΔV is the change in the volume
w = - (1.90 × 10⁵ N/m²) × (0.51 m³ - 0.18 m³) = -6.3 × 10⁴ J
The change in the internal energy (ΔU) is:
ΔU = q + w = 965 J + (-6.3 × 10⁴ J) = -6.2 × 10⁴ J
