Answer:
The new element will be thorium-226 (²²⁶Th).
Explanation:
The beta decay is given by:
![^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}](https://tex.z-dn.net/?f=%20%5E%7BA%7D_%7BZ%7DX%20%5Crightarrow%20%5E%7BA%7D_%7BZ%2B1%7DY%20%2B%20%5Cbeta%5E%7B-%7D%20%2B%20%5Cbar%7B%5Cnu_%7Be%7D%7D%20)
Where:
A: is the mass number
Z: is the number of protons
β⁻: is a beta particle = electron
: is an antineutrino
The neutral atom has 88 electrons, so:
![e^{-} = 88 = Z](https://tex.z-dn.net/?f=%20e%5E%7B-%7D%20%3D%2088%20%3D%20Z%20)
Hence the element is radium (Ra), it has A = 226.
If Ra undergoes 2 rounds of beta minus decay, we have:
Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).
I hope it helps you!
I can't see the picture, but in general, I believe it is in dropping from the first energy level above the ground state, to the ground state.
Thermal (heat) energy is ur answer mate
Hope it helps
Answer:
Option A = 14.19 atm
Explanation:
Given data:
Volume of gas = 2.50 L
Number of moles of gas = 1.35 mol
Temperature of gas = 320 K
Pressure of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values in formula.
P × 2.50 L = 1.35 mol × 0.0821 atm.L/ mol.K× 320
P = 35.467 atm.L/ 2.50 L
P = 14.19 atm
Thus, option A is correct.
Given the mass percentage of HCl solution = 15.00 %
This means that 15.00 g HCl is present in 100 g solution
Moles of HCl = ![15.00 gHCl*\frac{1 mol HCl}{36.46 g HCl} =0.411molHCl](https://tex.z-dn.net/?f=15.00%20gHCl%2A%5Cfrac%7B1%20mol%20HCl%7D%7B36.46%20g%20HCl%7D%20%3D0.411molHCl)
Density of the solution = 1.075 g/mL
Calculating the volume of solution from density and mass:
![100 g *\frac{1mL}{1.075 g} =93.0 mL](https://tex.z-dn.net/?f=100%20g%20%2A%5Cfrac%7B1mL%7D%7B1.075%20g%7D%20%3D93.0%20mL)
Converting volume from mL to L:
![93.0 mL * \frac{1 L}{1000 mL} =0.093 L](https://tex.z-dn.net/?f=93.0%20mL%20%2A%20%5Cfrac%7B1%20L%7D%7B1000%20mL%7D%20%3D0.093%20L)
Calculating the molarity of HCl solution from moles and volume:
![\frac{0.411 mol}{0.093 L} =4.42 mol/L](https://tex.z-dn.net/?f=%5Cfrac%7B0.411%20mol%7D%7B0.093%20L%7D%20%3D4.42%20mol%2FL)