We are given with
V = 12L
T = 298 K
P = 1000 kPa
We are asked to get the number of moles, n
We can solve this using the ideal gas law
PV = nRT
n = PV / RT
Simply substitute the values and use the appropriate value for R.
Where are the answer choices?
Lee? The verb should be in the el/Ella/usted form
Answer:
Demonstrate familiarity with the pH scale ... body (excluding things like stomach acid) measure around 7.2 and 7.6 on the pH scale (a 7 is neutral on the scale). ... The pH of a solution is a measure of its acidity or alkalinity (base). ... Using a pH meter, you find the pH of an unknown solution to be 8.0.
Explanation:
I Cant Answer your question but maybe this will help
Volume Changes for Gases
Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.
Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:
V1 = [n • R • (T1 - T0) ÷ P] +V0
Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:
V1 = [n • R • T ÷ (P1 - P0)] + V0
Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.
Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:
V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0
Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.
