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Rina8888 [55]
2 years ago
11

Write the point-slope form of an equation of the line through the points (-2, -3) and (-7, 4).

Mathematics
1 answer:
Ivenika [448]2 years ago
4 0
Answer:
7x+5y +29= 0
Step-by-step explanation: first we have to find slop of the line that is.( Y2-Y1)/x2-x1
M = slope = 4+3)/-7+2
M= 7/-5
Equation of line y - y 1 = M (X - X1)
Y+3 = 7/-5 (x+2)
7x + 5y +29 =0 Ans .

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NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=-4.9t2+64t+
ryzh [129]

Using the vertex of the quadratic equation, it is found that:

The rocket will reach its peak height of 345 meters above sea level at 6.53 seconds.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

x_v = -\frac{b}{2a}

y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is given by:

h(t) = -4.9t² + 64t + 136.

The coefficients are a = -4.9 < 0, b = 64, c = 136, hence the instant of the maximum height is given by, in seconds:

t_v = -\frac{64}{2(-4.9)} = 6.53

More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967

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7 0
3 years ago
(Middle school math) please help, thank you!
katrin2010 [14]

Answer:

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Step-by-step explanation:

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6 0
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If g(x)=11x+3 find g(x+7) and g(x)+g(7).
Liono4ka [1.6K]

Answer:

g(x + 7) = 11x + 80

g(x) + g(7) = 11x + 83

Step-by-step explanation:

g(x + 7) = 11(x + 7) + 3 = 11x + 77 + 3 = 11x + 80

g(x) + g(7) = 11x + 3 + 11(7) + 3 = 11x + 3 + 77 + 3 = 11x + 83

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3 years ago
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Pavlova-9 [17]

Let us use the formula with the point (4,5) and (0,2)

\begin{gathered} d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt[]{(4-0)^2+(5-2)^2} \\ =\sqrt[]{16+9}=\sqrt[]{25}=5 \end{gathered}

8 0
1 year ago
1/2 to exponent of 4
Neporo4naja [7]

Answer:

0.0625 is the answer.

Hope it helps you!!!

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3 years ago
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