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Sveta_85 [38]
3 years ago
8

If the height of the ramp is increased then the marble's speed will be greater because gravity will have less resistance when pu

lling the marble to the ground. What is the independent variable? Question 3 options: marble's speed gravity height of the ramp resistnace
Physics
1 answer:
Alik [6]3 years ago
7 0
If you increase the steepness of the ramp, then you will increase the acceleration of a ball which rolls down the ramp. This can be seen in two different ways: 

<span>1) Components of forces. Forces are vectors and have a direction and a magnitude. The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the gravitational force which points along the direction of the ball's motion can accelerate the ball. The other component pushes the ball into the ramp, and the ramp pushes back, so there is no acceleration of the ball into the ramp. If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. If the ramp is vertical, the ball just drops with acceleration due to gravity. These arguments are changed a bit by the fact that the ball is rolling and not sliding, but that only affects the magnitude of the acceleration but not the fact that it increases with ramp steepness. </span>

<span>2) Work and energy. The change in potential energy of the ball is its mass times the change in height (only the vertical component counts -- horizontal displacements do not change gravitational potential energy) times the local gravitational acceleration g. This loss of gravitational potential energy shows up as an increase in kinetic energy. If the ball falls a farther distance vertically, it will have a greater kinetic energy and be going faster. Again, the kinetic energy is shared between the motion of the ball going somewhere, and the rotation of the ball, and so the details of the acceleration depend on the ball (is it hollow or solid?), but the dependence on the steepness of the ramp is the same. </span>
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An ice cube measures 1.38 in. on each edge and weighs 1.39 oz. What is the density of the ice cube in g/cm^3
brilliants [131]

Answer:

0.91 g/cm³

Explanation:

Density: This can be defined as the ratio of mass of an object to its volume.

The mathematical expression for density is given as,

D = m/v .............................. Equation 1

Where D = Density of the ice cube, m = mass of the ice cube, v = volume of the ice cube.

v = l³

Where l = length of each side of the cube.

l = 1.38 in = (1.38×2.54) cm = 3.51 cm

v = 3.51³

v = 43.24 cm³

Given: m = 1.39 oz = (1.39×28.35) g = 39.41 g

Substitute into equation 1

D = 39.41/43.24

D = 0.91 g/cm³

Hence the density of the ice cube = 0.91 g/cm³

4 0
4 years ago
Juan draws a free-body diagram of an object that is in dynamic equilibrium moving to the left. Which labels correctly complete t
Goryan [66]

Y is -45 N and X is 30.

When learning about forces, you have to understand that everything will cancel out on an object. So if the normal force is 45, to cancel it, the force of gravity has to be the negative of it. The same idea goes to frictional force. If the frictional force is -30 N, then to cancel it out, it has to be 30 N.

3 0
3 years ago
Read 2 more answers
Help with the questions​
snow_lady [41]

Answer:

Try asking your mom cause Brainly isn't always right ! : )

Explanation:

She'll help you if you need it truly. She is there to help you.

6 0
3 years ago
Cómo puedo saber si el agua destilada que nos vendieron es destilada de verdad?
Pepsi [2]

Answer:

Caliente el agua del grifo hasta que se convierta en vapor. Cuando el vapor se vuelve a condensar en agua

Explanation:

7 0
3 years ago
If atmospheric pressure suddenly changes from 1.00 atm to 0.896 atm at 298 k, how much oxygen will be released from 3.30 l of wa
xxMikexx [17]
At  a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:

<span>S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M
</span>
At 0.890 atm,
<span>S = (H)(Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M</span>
<span>
If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows</span>
<span>
3.30 L x (0.000273 mol / L) = 0.0012012 mol</span>

3.30 L x (0.00024297 mol / L) = 0.001069068 mol

0.0012012 mol - 0.001069068 mol = 0.000132 mol
6 0
3 years ago
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