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irina [24]
3 years ago
15

An electric field is applied to a solution containing bromide ions. As a result, the ions move through the solution with an aver

age drift speed of 3.0 × 10−7 m/s. The mobility of bromide ions in solution is 8.1 × 10−8 (m/s)/(N/C). What is the magnitude of the net electric field inside the solution?
Physics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

The magnitude of the net electric field inside the solution is 3.704 N/C

Explanation:

Given;

average drift speed, v = 3 x 10⁻⁷ m/s

mobility of the bromide ions, μ = 8.1 x 10⁻⁸ (m/s)(N/C)

The magnitude of the net electric field inside the solution is given by the equation below;

E = \frac{v}{\mu}

where;

E is the magnitude of the net electric field inside the solution

Substitute the given values and solve for E

E = \frac{v}{\mu}\\\\E = \frac{3*10^{-7}}{8.1*10^{-8}}\\\\ E = 3.704 \ N/C

Therefore, the magnitude of the net electric field inside the solution is 3.704 N/C

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Explanation:

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3 years ago
Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the force of repulsion
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1micro \: =   {1}^{ - 6}

1q = 20 \times 10 {}^{ - 6}

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remember

k = 9 \times  {10}^{9}

change distance 150cm to 1.5m

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f =\frac{9 \times 10 {}^{9} \times 20  \times 10 {}^{ - 6} \times 100 \times  {10}^{ - 6}   }{1.5 {}^{2} }

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