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3 years ago

What a relationship between flame color and chemical name.

2 answers:

5 0

The flame gets the color which is determined by the properties of the atomic energy shells of the chemical element of the substance.

LekaFEV [45]3 years ago

3 0

Those transitions emit light of very specific frequencies, characteristic of the chemical element itself. Therefore, the flame gets the color, which is primarily determined by properties of the atomic energy shells of the chemical element of the substance being put into flame.

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A 5 newton force and a 7 newton force act concurrently on a point. As the angle between the forces is increased from 0 to 180 th

Reika [66]

Answer:

The magnitude of the resultant decreases from A+B to A-B

Explanation:

The magnitude of the resultant of two vectors is given by

$R=\sqrt{A^2 +B^2 +2AB cos \theta}$

where

A is the magnitude of the first vector

B is the magnitude of the second vector

$\theta$ is the angle between the directions of the two vectors

In the formula, A and B are constant, so the behaviour depends only on the function $cos \theta$ . The value of $cos \theta$ are:

- 1 (maximum) when the angle is 0, so the magnitude of the resultant in this case is

$R=\sqrt{A^2 +B^2+2AB}=\sqrt{(A+B)^2}=A+B$

- then it decreases, until it becomes 0 when the angle is 90 degrees, where the magnitude of the resultant is

$R=\sqrt{A^2 +B^2+0}=\sqrt{A^2+B^2}$

- then it becomes negative, and continues to decrease, until it reaches a value of -1 when the angle is 180 degrees, and the magnitude of the resultant is

$R=\sqrt{A^2 +B^2-2AB}=\sqrt{(A-B)^2}=A-B$

4 0

3 years ago

When considering the gas laws, the kelvin temperature scale must be used. the reason for this is that the kelvin scale is direct

suter [353]

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7 0

3 years ago

Acceleration of a free-falling object in a frictionless environment increases as a function of time.

Digiron [165]

A free-falling object is an object moving under the effect of gravitational forces alone

The correct option to select for the True or False question is False

The reason the above selected option is correct is as follows:

According to Newton's second law of motion, we have;

Force = Mass × Acceleration

The force of gravity is $F_{g} =G \cdot \dfrac{M \cdot m}{r^{2}}$

Where;

$G \cdot \dfrac{M }{r^{2}} = Acceleration \ due \ to \ gravity , \ g \approx 9.81 m/s^2$

m = The mass of the object

∴ The force acting on an object in free fall, $F_g$ = m × g

Therefore the acceleration of an object in free fall is the constant acceleration due to gravity, and it therefore, does not change with time

The correct option for the question, acceleration of a free-falling object in a frictionless environment increases as a function of time is <u>False</u>

<u></u>

Learn more about object in free fall here:

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6 0

2 years ago

Which subatomic particle can be absent from an atom?

Alika [10]

Neutron can be absent

5 0

3 years ago

6. Mr. Leppold jumps out of a plane with a parachute...before the chute opens,

polet [3.4K]

1) He has both potential and kinetic energy

2) Before the parachute opens, the potential energy decreases and the kinetic energy increases

Explanation:

The gravitational potential energy of a body is the energy possessed by the object due to its position in a gravitational field, and it is given by:

$PE=mgh$

where

m is the mass of the body

g is the acceleration of gravity

h is the height of the body above the ground

On the other hand, the kinetic energy of a body is the energy possessed by the body due to its motion; it is given by

$KE=\frac{1}{2}mv^2$

where

v is the speed of the object

Here Mr. Leppold has both potential and kinetic energy before opening the parachute, because:

- It is moving at a certain speed, so $v\neq 0$ , therefore he has kinetic energy

- He is at a certain height above the ground, $h\neq 0$ , therefore he has potential energy

The total mechanical energy of Mr.Leppold is the sum of the potential and the kinetic energy:

$E=PE+KE$

According to the law of conservation of energy, in absence of air resistance, this quantity remains constant.

During the fall, the height of Leppold decreases: this means that as $h$ decreases, the potential energy decreases too.

However, the total energy E must remain constant: therefore, this means that the kinetic energy KE must increase, and this occurs because the speed of Mr. Leppold increases as he falls.

Learn more about kinetic and potential energy:

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8 0

3 years ago