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Licemer1 [7]
3 years ago
13

g Using the absorbance vs wavelength spectrum where the 1st peak is slightly less intense than the 2nd peak, determine the wavel

ength, the absorbance value, and the dye color identification color for the two peaks in the unknown spectrum.
Physics
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

The wavelength range is always used to know the probable material present

Explanation:

The wavelength variation from with the concentration shows the type of material in as much the Spectrometer is well initialized before running the sample. The peaks interval may have effect on band gap.  

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An object from a certain height falls freely. which of the following happens PE and KE when the object is half on its way down​
Leto [7]

Answer:

A. <em>Loses PE and gains KE </em>

Explanation:

Statement is incomplete. Complete statement of problem is:

<em>1. An object from a certain height falls freely. Which of the following happens to PE  and KE when the object is half on its way down? </em>

A. <em>Loses PE and gains KE </em>

B. <em>Gains PE and loses KE </em>

C. <em>Loses both PE and KE </em>

D. <em>Gains both PE and KE​</em>

If we neglect the effects of any conservative force, the application of the Principle of Energy Conservation is reduced to a sum of gravitational potential (U_{g}) and translational kinetic energies, measured in joules. That is:

U_{g,1}+K_{1} =U_{g,2}+K_{2} (Eq. 1)

Let assume that an object falls from a height h with a speed of zero. By definitions of gravitational potential and translational kinetic energies the previous is expanded. If final height is the half of initial value, then:

m\cdot g\cdot h  = 0.5\cdot m\cdot g\cdot h +K_{2} (Eq. 1b)

K_{2} = 0.5\cdot m\cdot g\cdot h

K_{2} = 0.5\cdot U_{g,1}

In a nutshell, translational kinetic energy is increased at the expense of diminishing gravitational potential energy. The correct answer is A.

6 0
3 years ago
The tallest Ferris wheel in the world is located in Singapore. Standing 42 stories high and holding as many as 780 passengers, t
kakasveta [241]

Answer:

The speed of the riders on the Singapore Flyer is approximately 0.262 m/s

Explanation:

The dimensions of the tallest Ferris wheel in the world are;

The diameter of the Ferris wheel, D = 150 m

The tine it takes the Ferris wheel to make a full circle, T = 30 minutes = 30 min × 60 s/min = 1,800 seconds

The angular velocity of the Ferris wheel, ω = 2·π/T

The linear velocity of the Ferris wheel, v = r·ω = The speed of the riders

Where;

r = The radius of the Ferris wheel = D/2

D = 150 m

∴ r = 150 m/2 = 75 m

∴ v = r·2·π/T

∴ v = 75 m × 2 × π/(1,800 s) ≈ 0.262 m/s

The speed of the riders on the Singapore Flyer, v ≈ 0.262 m/s

8 0
3 years ago
If we heated the ball up and kept the ring room temperature, would the ball be able to fit through the ring? (1 point) Why or wh
Fed [463]

Answer:

no:

Explanation:

it would grow and no longer be able to fit through the loop due to the hot air expanding.

8 0
3 years ago
A golf ball flies through the air after being struck with a golf club. Which of the following statements describes the force on
valentina_108 [34]

Answer:

C) The force experienced by the ball equals the force experienced by the club.

Explanation:

When the golfer strikes the ball with his club, the club exerts a force on the ball. Due to Newton's Third Law Of Motion [Every Action has an equal and opposite reaction], the ball also exerts an equal force on the club. However,

As the mass of the club is usually greater than the mass of the ball, it accelerates slower; While the ball way faster, following the equation : F=ma

3 0
3 years ago
You illuminate a slit with a width of 0.0549 mm with a light of wavelength 735 nm and observe the resulting diffraction pattern
spayn [35]

Answer:

Explanation:

Given

slit width d=0.0549\ mm

wavelength of light \lambda =735\ nm

Screen is placed at a distance of D=2.85\ m

The angle for the first minima is given by

\sin \theta _1=\frac{m\lambda }{d}

for m=1

\sin \theta _1=\frac{1\times 735\times 10^{-9}}{0.0549\times 10^{-3}}

\sin \theta _1=0.0133

and one half of central maxima is given by

Y=D\sin \theta _1

Y=2.85\times 0.0133

Y=0.0381\ m

Width of central maxima =2Y

Width=0.0762\ m\approx 7.62\ cm                                

8 0
4 years ago
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