Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So
Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So
Find the probability that bridge B was used.
0.1333 = 13.33% probability that bridge B was used.
The Pythagorean theorem a²+b²=c²
16²+18²=c²
256+324 = 580
√580
24=4x-6
(add six both sides)
30=4x
(divide 4 both sides.)
7.5=x (roughly)
4/10 in simplest form is 2/5
6/20 in simplest form is 3/10
10/25 in simplest form is 2/5
Answer:
you got this sound from the human body for you so much I was wondering what to say I'm sorry I'm not going anywhere you want to go get me on snap now I got you can do this is the best of
Answer:
Step-by-step explanation:
Given x^2+4x+13=0, find the complex roots. The best approach here is to use the quadratic formula. Note that a = 1, b = 4 and c = 13.
Thus, the discriminant, b^2 - 4ac, is (4)^2 - 4(1)(13) = 16 - 52 = -36, and the square root of that is plus or minus i√36, or plus or minus 6i.
plus or minus i√
