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Gnesinka [82]
3 years ago
14

How do you do b,c, and d

Chemistry
1 answer:
Alika [10]3 years ago
8 0
I have no idea I know it’s gonna be a number
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In the balanced chemical equation for the formation of ammonia (NH3) from
blondinia [14]

Answer:

4

Explanation:

first write down the balanced equation:

N2 + 3 H2 → 2 NH3

when there is no coefficient written, there is actually an "invisible" 1 coefficient. so the coefficient of nitrogen (N2) is 1.

coefficient of N2 is 1 and the coefficient of H2 is 3.

then sum coefficients!

5 0
3 years ago
Can someone pls explain? :'(
telo118 [61]
It is 0.07 g for your answer
7 0
3 years ago
All organic molecules contain carbon and hydrogen. what parts of an organic molecule may contain oxygen, nitrogen, or phosphorus
Minchanka [31]
Answer is: <span>functional groups.
</span>Functional groups<span> are specific </span>groups<span> that are responsible for the characteristic chemical properties of molecule.</span>
<span>Proteins have nitrogen and oxygen in functional group.
Nucleic acids and some lipids have phosphorus in fuctional group.
Carbohydrates have oxygen in functional group for example.</span>
7 0
3 years ago
Read 2 more answers
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
4 years ago
Help me with 4,5 plz
Helen [10]
The answer to 4 is A.                                              
The answer to 5 is C.
7 0
3 years ago
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