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LUCKY_DIMON [66]
2 years ago
9

sedimentary rocks that are formed from physical/chemical process within the earth are given the general name of

Chemistry
2 answers:
Sedaia [141]2 years ago
5 0

Answer:

clastic

Explanation:

Karolina [17]2 years ago
3 0

Answer:

cementation

Explanation:

part of the rock cycle

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The vapor pressure of water and the partial pressure of hydrogen contribute to the total pressure of 715 torr. What is the parti
Lostsunrise [7]

Answer:

0.91 atm is the partial pressure of just hydrogen gas.

Explanation:

Vapor pressure of water , p= 0.0313 atm

Partial pressure of hydrogen gas = p_{H_2}

Total pressure of the water vapors and hydrogen gas = P = 715 Torr

1 atm = 715 Torr

715 Torr=\frac{715}{760} atm=0.94 atm

According Dalton's law of partial pressure:

P=p+p_{H_2}

0.94 atm=0.0313 atm+p_{H_2}

p_{H_2}=0.94 atm - 0.0313 atm =0.9087 atm \approx 0.91 atm

0.91 atm is the partial pressure of just hydrogen gas.

8 0
3 years ago
How many atoms does Iron oxide have?
ArbitrLikvidat [17]
Added together = 159.7 grams for one mole of Fe2O3<span>. That is moles of hematite, but the question is about iron. We can see there are </span>two<span> iron atoms for every hematite molecule. So the number (moles) of iron atoms is twice the moles of the hematite molecules. 

so depending on how much you initially have will determine the answer</span>
7 0
3 years ago
Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm <br> This is a Boyle’s law gas problem
morpeh [17]
P1/V1=P2/V2
1/22.4=4/x
X=4 multiple by 22.4
V2=89.6L
3 0
3 years ago
If 22.5L of nitrogen at 0.98 atm is compressed to 0.95 atm,what is the new volume?
Ksenya-84 [330]

At constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

<h3>What is Boyle's law?</h3>

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given that;

  • Initial volume of the gas V₁ = 22.5L
  • Initial pressure of the gas P₁ = 0.98atm
  • Final pressure of the gas P₂ = 0.95atm
  • Final volume of the gas V₂ = ?

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = (0.98atm × 22.5L) / 0.95atm

V₂ = 22.05Latm / 0.95atm

V₂ = 23.2L

Therefore, at constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

Learn more about Boyle's law here: brainly.com/question/1437490

#SPJ1

6 0
2 years ago
If 11g of a gas occupies 5.6dm'3at s.t.p., calculate it's vapour density (1.0mol of a gas occupies 22.4dm'3at s.t.p.).​
11111nata11111 [884]

Answer:

{ \boxed{ \bf{vapour \: density = 2 \times molecular \: mass}}} \\{ \tt{ PV= (\frac{m}{ m_{r}}) RT}} \\ { \tt{3 \times 5.6 =  \frac{11}{m _{r}}  \times 0.0831 \times 273}} \\ { \tt{m _{r} = 14.85 \: g}} \\  \\ { \bf{vapour \: density = 2 \times m _{r}}} \\  = 2 \times 14.85 \\  = 29.7 \: { \tt{g {dm}^{ - 3} }}

7 0
3 years ago
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