Answer:
water and air
Explanation:
The examples of medium from this problem is water and air.
A medium is an agency or a means of propagating energy, waves or even facilitating a chemical reaction.
Fluids are very good medium in chemistry for chemical reactions. The two most common media used are air and water.
In physics, a vacuum is an empty space that has been evacuated. It also serves as a medium to study some physical phenomenon.
Answer:
1.33 × 10⁻³¹ m
Gamma rays
Explanation:
1 mol of photons required for the photoionization of N₂ has an energy (E) of 1495 kJ = 1495 × 10³ J = 1.495 × 10⁶ J. We can find the wavelength (λ) associated with this energy using the Planck-Einstein equation.
E = h . c . λ⁻¹
where,
h is the Planck's constant
c is the speed of light
E = h . c . λ⁻¹
λ = h . c . E⁻¹ = (6.63 × 10⁻³⁴ J.s) . (3.00 × 10⁸ m/s) . (1.495 × 10⁶ J)⁻¹ = 1.33 × 10⁻³¹ m
This wavelength corresponds to the Gamma rays region of the spectrum.
Answer:
more energy is absorbed when the bonds in the reactants are broken
The equation Eºcell = 0.0592/n logK must be used to find n and also Eºcell
2 Al(s) + 3 Mg2+(aq) → 2 Al3+(aq) + 3 Mg(s) Al3+ +3e- --> Al Eº = -1.66 V Mg2+ +2e- -->Mg Eº = -2.37V
To balance the equation, 6 moles of electrons must be transferred (2 Al and 3 Mg). This will be the value of n in the equation.
To find Eºcell, you need the reduction potentials which should be given in a table, and given above. Eºcell = -1.66 - (-2.37) = 0.71 V log K = Eºcell x n/0.0592 = 0.71 x 6/0.0592 log K = 71.95 K = 10^71.95 K = 1.1x10^72