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Agata [3.3K]
3 years ago
13

You and your lab group have been asked to design an investigation to determine the effects of heat transfer between two differen

t objects.
Which of the following investigation designs explains the heat transfer when atoms directly touch?
А
Boiling water, in a pan, sitting on a lit Bunsen burner.
B
Boiling water, in a pan, in front of a lit Bunsen burner.
С
Hands warming in front of a lit Bunsen burner.
D
Hands touching the handle of pan sitting on a lit Bunsen burner.
Chemistry
1 answer:
GREYUIT [131]3 years ago
5 0
I believe that answer is D
The heat from the Bunsen burner transfers to the water and the pot, then the heat from the pot transfers to the person’s hand.
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3 years ago
Calculate the volume of 1 M NaOH needed to prepare 10.0 ml of a 0.10 M solution.
Mumz [18]
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
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V₁(NaOH) = 1 ml.
7 0
3 years ago
Why cant atoms of one element convert to another element?
N76 [4]
They can be converted, it's called nuclear transmutation.
4 0
3 years ago
Read 2 more answers
A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the
Sedbober [7]

<u>Answer:</u> The final temperature will be 52.74^oC

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

q=m\times C\times (T_2-T_1)

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

q_1=-q_2

OR

m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2) ......(1)

where,

C = heat capacity of water = 4.184J/g^oC

m_1 = mass of water of sample 1 = 100.0 g

m_2 = mass of water of sample 2 = 71.0 g

T_f = final temperature of the system = ?

T_1 = initial temperature of water of sample 1 = 27^oC

T_2 = initial temperature of the water of sample 2 = 89.0^oC

Putting values in equation 1, we get:

100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC

Hence, the final temperature will be 52.74^oC

6 0
3 years ago
How many grams of a 19.6% sugar solution contain 72.5 g of sugar?
anzhelika [568]

Answer:

6.2g of sugar solution contains 72.5g

4 0
3 years ago
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