A) Add three <em>line</em> segments (AD, CF, BE) to the <em>regular</em> hexagon.
B) The area of each triangle of the <em>regular</em> hexagon is 35.1 in².
C) The area of the <em>regular</em> hexagon is 210.6 in².
<h3>How to calculate the area of a regular hexagon</h3>
In geometry, regular hexagons are formed by six <em>regular</em> triangles with a common vertex. We decompose the hexagon in six <em>equilateral</em> triangles by adding three <em>line</em> segments (AD, CF, BE).The area of each triangle is found by the following equation:
A = 0.5 · (9 in) · (7.8 in)
A = 35.1 in²
And the area of the <em>regular</em> polygon is six times the former result, that is, 210.6 square inches.
To learn more on polygons: brainly.com/question/17756657
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Answer:
where is the n in the equation?
Step-by-step explanation:
Answer:
y=1
Step-by-step explanation:
you can use those points to find the slope
use the equation
then plug in the numbers
so (1-1)/(-8-7) = 0/15 so the slope is zero meaning it is a horizontal line which we can tell logically because the y coordinates of both points are 1.
so if you plug those numbers into the formula y=mx+b where m is slope and b is the y intercept then
you get y=0*x+1
then 0*x is just zero and it goes away so the equation for this line is y=1
Hope this helps! :)
Steps:
Simplify:
5³/5⁷
= 5³/5⁷
= 5*5*5/ 5*5*5*5*5*5*5
=1/5⁴
=1/625 (Decimal: 0.0016)
Steps by Step:
5³/5⁷
=125/5⁷
=125/78125
=1/625
Answer: =1/625 (Decimal: 0.0016)
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<em><u>Hope this helps.</u></em>