A cylindrical metal pipe has a diameter of 8.4 millimeters and a height of 10 millimeters. A hole cut out of the center has a di
ameter of 6 millimeters. What is the volume of metal in the pipe? Use 3.14 for π and round the answer to the nearest tenth of a cubic millimeter. mm3
2 answers:
Answer:
271.3 mm^3
Step-by-step explanation:
Volume of a cylinder = πr^2h
To find the answer, we need to find the difference between the large cylindrical and small cylindrical pipes.
V = π h (R^2 – r^2)
Given: h= 10, R is outer radius = 8.4/2 = 4.2, r is inner radius = 6/2 = 3
V = π (10) (4.2^2 – 3^2)
V= 3.14*10(17.64 - 9)
V = 31.4(8.64)
V = 271.3 mm^3
The volume of metal in the pipe 271.3 mm^3
Hope this will helpful.
Thank you.
To solve this problem, we simply use the equation of
volume for hollow cylinders:
V = π h (R^2 – r^2)
where V is volume, h is height = 10, R is outer radius =
8.4/2 = 4.2, r is inner radius = 6/2 = 3
V = π (10) (4.2^2 – 3^2)
<span>V = 86.4π = 271.43 mm^3</span>
You might be interested in
Answer:
F(x)=8(x-3)
Step-by-step explanation:
Had to watch a video but I THINK this is the correct answer
Answer:
-15
Step-by-step explanation:
Answer:
where is the question????
Answer:
2
Step-by-step explanation:
there is 2: 3<u> 1 </u>
4
Hello!
You first cross multiply
4 * 7 = 28
5 * r = 5 * r
r * 5 = 28
Divide both sides by 5
r = 28/5 = 5.6
The answer is 28/5 or 5.6
Hope this helps!