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3 years ago

Which answer is the slope-intercept form for the given equation? 13x+2y=43

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

The slope intercept form of $13x+2y=43$ is $y=-\frac{13}{2}x+\frac{43}{2}$ .

Step-by-step explanation:

The given equation is

$13x+2y=43$

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

$13x+2y=43$

Subtract 13x from both sides.

$13x+2y-13x=-13x+43$

$2y=-13x+43$

Divide both sides by 2.

$y=-\frac{13}{2}x+\frac{43}{2}$

Therefore the slope intercept form of $13x+2y=43$ is $y=-\frac{13}{2}x+\frac{43}{2}$ .

yanalaym [24]3 years ago

3 0

Y=-13/2x+43/2 I hope this helped :3

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In △ABC, m∠A=19°, a=13, and b=14. Find c to the nearest tenth.

34kurt

We know that
Applying the law of sines

step 1
Find the value of angle B
a=13
b=14
A=19°
so

$\frac{a}{sin A} = \frac{b}{sin B} \\ a*sin B=b*sin A \\ sin B= \frac{b}{a}*sin A \\ sin B= \frac{14}{13} *sin 19 \\ sin B=0.3506 \\ B=arc sin(0.3506) \\ B=20.5$ °

step 2
with angle A and angle B find the angle C
A+B+C=180-----> solve for C
C=180-(A+B)------> C=180-(19+20.5)-----> C=140.5°

step 3
$\frac{a}{sin A} = \frac{c}{sin C} \\ a*sin C=c*sin A \\ c=a* \frac{sin C}{sin A} \\ c=13* \frac{sin 140.5}{sin 19} \\ c=25.4$

the answer is
the value of c is 25.4

3 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt

Goryan [66]

Answer:

A) The value of a is 29.

B) The value of b is greater than 29.

C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

$a-9=20$

We have to solve for a.

$a-9=20$

By using addition property of equality, we will add both side by 9;

$a-9+9=20+9\\a=29$

Hence the value of a is 29.

Solving for Part B.

Given,

$b-9>20$

We have to solve for b.

$b-9>20$

By using addition property of inequality, we will add both side by 9;

$b-9+9>20+9\\b>29$

Hence the value of b is greater than 29.

Solving for Part C.

In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

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3 years ago

If the perpendicular bisector of one side of a triangle goes through the opposite vertex, then is the triangle ( sometimes, alwa

avanturin [10]

It is always isosceles because it can be proved as follows:

The perpendicular bisector dissects the triangle into two, and it is the common side. Then each side of the bisector is 90 degrees, and the bisected to two equal sides, so the two dissected triangles are congruent, hence the original triangle is isosceles.

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igor_vitrenko [27]

Ya totally your cool bro

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3 years ago

What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)

kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

$l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2) \right )^{2}+\left (6-2 \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}$

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

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3 years ago