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LiRa [457]
3 years ago
12

Why do physicists say mass is more fundamental than weight??

Physics
1 answer:
fomenos3 years ago
7 0

Answer:

because mass of a matter never changes

on the other hand the weight of a matter changes due to gravity

for example the

on the moon the pull of gravity is less than it is on earth so the Weight of an object will be less on the moon but the mass of it will stay the same

Explanation:

I

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A wire carries a current of 6.91 A in a direction that makes an angle of 19◦ with the direction of a magnetic field of strength
g100num [7]

Answer:

4.454 N.

Explanation:

The force on a current carrying conductor in a magnetic field is given as,

F = BILsinФ................... Equation 1

Where F = magnetic Force, B = magnetic Field, I = current, L = Length of the wire, Ф = The angle between the conductor and the Field.

Given: B = 0.289 T, I = 6.91 A, L = 6.7 m, Ф = 19°

Substitute into equation 1

F = 0.289(6.91)(6.7)sin19

F = 0.289×6.91×6.7×0.33

F = 4.454 N.

Hence the magnetic force = 4.454 N.

6 0
4 years ago
The only force acting on a 1.9 kg canister that is moving in an xy plane has a magnitude of 3.9 N. The canister initially has a
Hunter-Best [27]

Answer:

The work done on the canister is 15.34 J.

Explanation:

Given;

mass of canister, m = 1.9 kg

magnitude of force acting on x-y plane, F = 3.9 N

initial velocity of canister in positive x direction, v_i = 3.9 m/s

final velocity of the canister in positive y direction, v_j = 5.6 \ m/s

The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.

ΔK.E = W_{net}

ΔK.E = K.E_f -K.E_i

The initial kinetic energy of the canister;

K.E_i = \frac{1}{2} mv_i^2\\\\K.E_i = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\  )^2\\\\K.E_i = \frac{1}{2} *1.9(\sqrt{3.9^2 +0^2 + 0^2}\  )^2 = 14.45 \ J

The final kinetic energy of the canister;

K.E_f =\frac{1}{2} mv_j^2 \\\\K.E_f = \frac{1}{2} m(\sqrt{v_i^2 +v_j^2 + v_z^2}\  )^2\\\\K.E_f = \frac{1}{2} *1.9(\sqrt{0^2 +5.6^2 + 0^2}\  )^2 = 29.79 \ J

ΔK.E = 29.79 J - 14.45 J

ΔK.E = W_{net} = 15.34 J

Therefore, the work done on the canister is 15.34 J.

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