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Sveta_85 [38]
4 years ago
15

Which lens can produce a virtual image and a real image?

Physics
2 answers:
Licemer1 [7]4 years ago
4 0

Answer:

Explanation:

When the two rays of light actually meets after refraction from a lens, the image is said to be real.

When the two rays of light appears to meet after refraction from a lens, the image is said to be virtual.

A concave lens always forms a virtual image, because it diverge the rays of light.

A convex lens forms a real image when the object placed between infinity and the focus of lens but t forms a virtual image when the object is placed between optical centre and the focus of the lens.

diamong [38]4 years ago
4 0

Answer:

Convex APEX Verified

Explanation:

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If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
Why does a curve on a distance-time graph indicate acceleration? an increasing amount of time passes for each unit of distance a
elena55 [62]

because speed can change overtime for a car, and isn't always constant.

8 0
3 years ago
Read 2 more answers
The intensity of sunlight incident on the surface of a solar panel on your roof is 1000 W/m^2. Calculate the sunlight energy abs
melisa1 [442]

Answer:

8.64 x 10^7 J

Explanation:

Intensity of sunlight, I = 1000 W/m^2

Length of panel, L = 6 m

Width of panel, W = 4 m

Area of the panel, A = L x W = 6 x 4 = 24 m^2

time, t = 1 hour = 3600 second

Energy = Intensity x area of panel x time

E = 1000 x 24 x 3600 = 8.64 x 10^7 J

5 0
4 years ago
A constant force of 40N acting on a body initially at rest gives it an acceleration of 0.1m/s inverse 2 for 4s .calculate the wo
kicyunya [14]

Correct Answer: Option C

<em>Explanation </em>

X = ut + 12at2

= (0 x 4) + (12 x 0.1 x 4 x 4)

= 0.8m

workdone = force x distance

= 40 x 0.8

= 32J

7 0
3 years ago
What is the voltage across six 1.5-V batteries when they are connected (a) in series, (b) in parallel, (c) three in parallel wit
Katyanochek1 [597]

Answer:

(a) 9.0 V (b) 1.5 V (c) 6.0 V

Explanation:

Here we use the simple concept of Kirchhoff's voltage law that potential in series will be added and potential in parallel will be same always. By this concept we answer all 3 parts of this question.

(a) When six 1.5 V batteries are is series means their potential is added.

So, Voltage across six batteries is

\triangle V = 1.5 V +1.5 V +1.5 V +1.5 V +1.5 V +1.5 V

\triangle V = 9.0 V

So, Net voltage is 9.0 Volts.

(b)When six 1.5 V batteries are in parallel then the net voltage across them will be voltage of either battery.

So, Voltage is

\triangle V = 1.5 V

Net voltage is 1.5 Volts.

(c) Now 3 are in series and 3 are in parallel,

the Net voltage of parallel is 1.5 V , now it behaves like <u>four </u>1.5 V are in series so the net voltage become

\triangle V = 1.5 V +  1.5 V +1.5 V +1.5 V

\triangle V = 6.0 V

Net voltage is 6.0 Volts.

6 0
3 years ago
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