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Iteru [2.4K]
3 years ago
10

HOTELS The Lincoln’s hotel room costs $90 a night. An additional 10% tax is added. Hotel parking is $12 per day. The Lincolns ex

pect to spend $30 in tips during their stay. Solve the inequality 90x + 90(0.1)x + 12x + 30 600 to find how many nights the Lincolns can stay at the hotel without exceeding total hotel costs of $600.
Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer:

5 nights

Step-by-step explanation:

Solve the inequality:

90x + 90(0.1)x + 12x + 30 \leq 600

Add like terms:

102x + 30 + 90(0.1)x \leq 600

Isolate the variables:

102x + 90(0.1)x \leq 570

102x + 9x \leq 570

111x \leq 570

x \leq 5.13

So, the Lincolns can stay for 5 nights without exceeding $600

You might be interested in
What expression is equivalent to 3-(-2+5)
maxonik [38]

Answer:

Ok ok, I see. So the answer is -9.

Step-by-step explanation:

We know the expresion is:

-3(-2+5)

We need to distrubute the -3 to what is in the parthese.

When I say distribute, basically you need to multiply the numbers inside the parethese by -3. So we can think of it as:

-3*-2=6

and:

-3*5=-15

Which we can rewrite as:

(6-15)

Subtract 15 from 6 and you get -9:

6-15=-9

Sorry hope this helps!

4 0
2 years ago
Translate the expression 5X -7 into words
Sonja [21]
A translated expression of the following into words would be
Subtract five x by seven.

Hope this helped :)
5 0
3 years ago
Complete the system that models the heights of the ball and the receiver’s hands over time. h = -16t² 14t h = -16t² t
bogdanovich [222]

Answer: The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.

The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8

4 0
2 years ago
2w-5=25<br> 10<br> 15<br> -15<br> -10<br> No solution <br> All real number
mihalych1998 [28]

Answer:

w=15

Step-by-step explanation:

2w-5=30

2×15-5=30

30-5=25

w=15

6 0
3 years ago
Read 2 more answers
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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