Question

Antoine went on vacation to Las Vegas. His room cost $115.62 each night. His flight there cost $45.70 and his flight home was $32.49. He averaged $15.00 per day on food. On the first day Antoine won $75.00 and on the last day he lost $25.00. If he stayed for 3 nights and 4 days, how much did the entire trip (including airfare, food, hotel, and winnings) cost him?

Answer 1

Answer:

The entire trip cost him $435.05.

Step-by-step explanation:

Consider the provided information.

His room cost $115.62 each night. Thus, the room cost for 3 night is:

$115.62 × 3 = $346.86

His flight there cost $45.70 and his flight home was $32.49. Thus, the total money he spends on the flight is:

$45.70 + $32.49 = $78.19

He spends $15.00 per day on food. Thus, the total money he spends in 4 days is:

$15 × 4 = $60

He won $75 on the first day but lost $25 on the last day. So the total money he got is:

$75 - $25 = $50 won

Now add all the expenses and winnings:

$346.86 + $78.19 + $60 - $50 = $435.05

Hence, the entire trip cost him $435.05.

Answer 2

The total amount is the sum of the cost of three nights in the hotel, $346.86, the flight costs, $45.70 + $32.49 = $78.19, and four days of food, $60, the amount he lost, $25, less the amount he won, $75. Calculating,
                      ($346.86 + $78.19 + $60 + $25) - ($75) = $435.05