Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2
The first choice is the contains only irrational number
The answer is 14. This is because 63=3+x+3x-4. Then You just subtract it and then you get 64=4x. Then you just divide it and then you get x=16.
Answer:
B: 6.0
Step-by-step explanation:
-3t^2+9t+54 = 0
This is the equation that needs to be solved
Divide both sides by -3
t^2 - 3t - 18 = 0
The factors of 18 are: (1 18) (2 9) (3 6)
3 - 6 = -3 and 3 x -6 = -18
So: (t + 3) (t - 6) = 0
t = -3, 6
It can't be negative so the answer is 6
Answer:
x^2 -4x +4
Step-by-step explanation:
(x-2)(x-2)
x^2 -2x -2x +4
x^2 -4x +4