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777dan777 [17]
3 years ago
7

Which is an equivalent equation solved for g?

Mathematics
2 answers:
Tasya [4]3 years ago
7 0
Where is the original equation

e-lub [12.9K]3 years ago
4 0

Answer: At/60 = g

Step-by-step explanation:

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The original price of a pair of shoes is $42. The sale price 20% off the orginal price. Sales tax of 7% is added to the sale pri
m_a_m_a [10]

Answer:

$8.40 is the amount to be subtracted from the $42.00. If you multiply 20% (.20) by $42.00 you get $8.40. To get your final price subtract $8.40 from $42.00 to get you final answer. I hope that helps.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The lifespans of gorillas in a particular zoo are normally distributed. the average gorilla lives 20.8 years; the standard devia
dezoksy [38]

Answer:

Step-by-step explanation: 2.35%+95%

Answer is 97.35%

5 0
3 years ago
Evalute the experssion -280+12x=
Alina [70]
The answer is 23 1/3. First, you need to add 280 to both sides of the equations in order cancel out 280 and get 12x by itself. But remember whatever you do to one side of an equation, you must to do the other. So now you have 12x=280. Now divide both sides of the equation by 12 in order to get x completely isolated. 280 divided by twelve is 23 1/3.

4 0
3 years ago
Select all possible values for x in the equation x^3=375?
Helga [31]
<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

<h2>Why?</h2>

To solve the problem, we need to remember the following properties of the exponents and roots:

a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}

Then, we are given the expression:

x^{3}=375

So, finding "x", we have:

x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}

Hence, the possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

Have a nice day!

7 0
4 years ago
The population p (in millions) of Italy from 1990 through 2008 can be approximated by the model p=56.8e^o.oo15t , where t repres
dimulka [17.4K]

As we already have the model that describes the change of the population in Italy in terms of the years that have elapsed, we only have to replace the conditions that are requested in that equation.

Therefore to find the population of Italy in the year 2000 (t = 10 years)  substitute t = 10 in the equation and have:

p = 56.8e^{0.0015*10}\\

p=57.6584 million people

To find the population of Italy in 2008 (t = 18 years)

substitute t = 18 in the equation and have:

p=56.8e ^{0.0015*18}\\

p=58.3545 million people


To predict the population in Italy for 2015 and 2020 with this model, we substitute in the equation t = 25 and t = 30

t = 25

p=56.8e^{0.0015*25}

p=58.9704 million people


 t = 30

p=56.8e^{0.0015*30}

p=59.4144 million people

8 0
3 years ago
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