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777dan777 [17]
3 years ago
7

Which is an equivalent equation solved for g?

Mathematics
2 answers:
Tasya [4]3 years ago
7 0
Where is the original equation

e-lub [12.9K]3 years ago
4 0

Answer: At/60 = g

Step-by-step explanation:

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The temperature T of a refrigerator is at least 35°F and at most 41°F. Write a compound
s344n2d4d5 [400]

The compound inequality for the temperature T of a refrigerator that is at least 35°F and at most 41°F is 35  ≤  T ≤  41

A compound inequality has two inequality statements joined together

The the temperature of the inequality is represented by T

The temperature T of a refrigerator is at least 35°F and at most 41°F

This means that the temperature falls between 35°F and 41°F

Since the temperature, T, is at most 41°F

This can be mathematically interpreted as

T  ≤  41

The temperature, T, is at least 35°F

35  ≤  T

Combining the two inequality statements 35  ≤  T and T  ≤  41, the compound statement formed is:

35  ≤  T ≤  41

The compound inequality for the temperature T of a refrigerator that is at least 35°F and at most 41°F is 35  ≤  T ≤  41

Learn more here: brainly.com/question/11316045

8 0
3 years ago
Find the value of a given <img src="https://tex.z-dn.net/?f=5%5Ea%5C%5C" id="TexFormula1" title="5^a\\" alt="5^a\\" align="absmi
ddd [48]

Answer:

  a = 2/3

Step-by-step explanation:

A cube root is the same as a 1/3 power. The square of that gives a 2/3 power.

  a = 2/3

_____

<em>Additional comment</em>

You can see the relationship between a root index and an exponent if you consider what the root means.

Consider a cube root, for example. When you cube the root, you get the original number:

  (∛x)·(∛x)·(∛x) = x

Now, let's write the root as a power of x: x^a.

  (x^a)·(x^a)·(x^a) = x . . . . . where x^a = ∛x

We know this product is ...

  x^(a+a+a) = x^(3a) = x^1

This tells us that ...

  3a = 1   ⇒   a = 1/3

That is, ∛x = x^(1/3).

Of course an n-th root is multiplied by itself n times to get the original number, so the corresponding exponent is x^(1/n).

5 0
2 years ago
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