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Dmitriy789 [7]
4 years ago
7

Write the quadratic function in vertex form. y = x^2 - 14x + 53

Mathematics
1 answer:
Soloha48 [4]4 years ago
8 0
Complete the square

y=(x^2-14x)+53
take 1/2 of -14 and square it and add negtive and postive inside arenthasees
y=(x^2-14x+49-49)+53
complete the square
y=(x-7)^2-49+53
y=(x-7)^2+4
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Answer:

  see attached

Step-by-step explanation:

The equation can be rewritten to vertex form, so you can tell the vertex is at (2, -5). The leading coefficient of 2 means the points will be twice as far apart vertically than they would be if the leading coefficient were 1. A couple of points are shown in the attached.

  y = 2(x^2 -4x) +3

  y = 2(x^2 -4x +4) +3 -8 . . . . . . complete the square

  y = 2(x -2)^2 -5 . . . . . . . . . . . . finish putting in vertex form

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3 years ago
Will give brainliest please help! <3
creativ13 [48]
Hi love! I believe it’s A. If not please report back. Thank you!
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Jasmine would need $17 .

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4 years ago
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GrogVix [38]

Answer:

One solution

Step-by-step explanation:

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