Answer:
1/63
Step-by-step explanation:
Here is the complete question
In an experiment, the probability that event A occurs is 1
/7 and the probability that event B occurs is 1
/9
.
If A and B are independent events, what is the probability that A and B both occur?
Simplify any fractions.
Solution
the probability of independent events A and B occurring is P(A u B) = P(A)×P(B) where P(A) = probability that event A occurs = 1
/7 and P(B) = probability that event B occurs = 1
/9
.
So, P(A u B) = P(A)×P(B) = 1/7 × 1/9 = 1/63
Answer:
x=-4.22222
The 2 is repeating
Step-by-step explanation:
First you subtract 18 from both sides
9x=--38
Then divide both sides by 9
x=-4.22222
The 2 is repeating
Step-by-step explanation:
P(t) = 12,000 (2)^(-t/15)
9,000 = 12,000 (2)^(-t/15)
0.75 = 2^(-t/15)
ln(0.75) = ln(2^(-t/15))
ln(0.75) = (-t/15) ln(2)
-15 ln(0.75) / ln(2) = t
t = 6.23
Answer: x = 9.8181......
Step-by-step explanation:
(44)x =432
Take out Parentheses:
44x = 432
Divide both sides by 44:
x = 9.8181......
(4,4)736472i would help but i jus points to do my homework lol