Patent ductus arteriosus occurs when the normal fetal circulation conduit between the pulmonary artery and the aorta fails to close and results in increased pulmonary blood flow. The clinical manifestations of patent ductus arteriosus include; Murmur; wide and bounding pulse pressure, Asymptomatic Heart failure.
As we know that
<span>P total = pO +pH +pN</span>
<span>so</span>
P = P1 + P2 + P3
378 kPa= 212 kPa + 101 kPa + P(H2)
P(H2) = 65 kPa
partial pressure is 65
so correct option is A
hope it helps
Answer;
The correct answer would be Rr.
In a monohybrid cross, the phenotype ratio of 3:1 is obtained only when both the parents are heterozygous for the trait.
In this condition, the heterozygous genotype would be Rr. The phenotype of both the parents would be round seeds (R) as the round is a dominant trait.
The cross of these parents would produce offspring with three types of genotypes RR, Rr, and rr in ratio 1:2:1.
Thus, the phenotypic ratio would come out to be 3 (round seed):1 (wrinkled seed).
Answer: Abiotic
Explanation: Prairie soil is Non-living, therefore making it Abiotic!
Biotic also means living btw.