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bixtya [17]
4 years ago
14

addition of a catalyst to a reaction and increasing the temperature of a reaction generally have the same effect on the reaction

rate. T or F
Chemistry
1 answer:
son4ous [18]4 years ago
5 0
I believe this is true, this is one of the reasons as for why we as humans posses catalysts, biological enzymes that can help speed up reactions by lowering the energy required for the reaction to start. Without them, then basically one of the only other ways to increase the reaction rate would be to substantially increase the temperature to allow these fundamental chemical and metabolic reactions to occur.
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Take the molar mass of U and add it to the molar mass of F(3).
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How many grams of beryllium phosphate are produced when 38 grams of beryllium oxide react with iron (III) phosphate?
Irina-Kira [14]

solve using the chemical equation and molar mass

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3 0
3 years ago
Cross aldol condensation reaction was carried out by reacting Acetone with Benzaldehyde in presence of sodium hydroxide. How man
natta225 [31]

Answer:

Carbons 1 and 3

Explanation:

We must remember that by definition <u>alpha carbon</u>s are the carbon (or carbons) next to the carbon that contains the main group. In this case, the main group is the carbonyl group (C = O) in the middle of the molecule. In the acetone molecule, we have three carbons, the carbons neighboring the carbon of the carbonyl group (carbon two) will be the <u>alpha carbons</u>. (Red and blue carbons or carbons one and three)

See figure 1 for further explanations.

I hope it helps!

4 0
4 years ago
What steps would you take in a lab to prepare 1000 mL of a 2 M NaCl solution
amm1812

Answer:

The answer to your question is below

Explanation:

Data

Volume = 1000 ml

Concentration = 2M

molecule = NaCl

Process

1.- Calculate the number of moles of NaCl

Molarity = moles/Volume

-Solve for volume

moles = Molarity x Volume (liters)

-Substitution

moles = 2 x 1

-Result

moles = 2

2.- Determine the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

3.- Calculate the mass of NaCl to prepare the solution

               58.5 g -----------------  1mol

                   x      -----------------  2 moles

                       x = (2 x 58.5) / 1

                       x = 117g

4.- Weight 117 g of NaCl, place them in a volumetric flask (1 l), and add enough water to prepare the solution.

7 0
4 years ago
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