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Step2247 [10]
3 years ago
7

In ionic bonding

Chemistry
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

E. A noble gas configuration is formed for each element or ion.

Explanation:

An ionic bond is <em>an electrostatic force that holds ions together in an ionic compound.</em>

This ionic bonding is produced between a low electronegativity element, which gives one or more electrons transforming into a cation. A high electronegativity element receives one or more electrons transforming into an anion.

By the Lewis-octet rule, when elements join to form a compound they <u>acquire the noble gas configuration of the closest noble gas</u>.

For example, magnesium loses two electrons to form Mg²⁺, and its configuration is the same as that of neon (Ne) gas.

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Calculate the molarity of 0.060 moles of sodium bicarbonate (NaHCO3) in 1500. mL of solution.
inna [77]

Answer: 0.040 mol/l

Explanation: Molarity c = n/V (Concentration)

c = 0.060 mol / 1,5 l = 0,040 mol/l

5 0
3 years ago
On which side of an equation are the reactants found?
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What is the percent by volume of alcohol, in a solution containing 24 mL of alcohol dissolved in 90 mL of water?
Dmitry [639]

Answer:

use this formula it will help u .

Explanation:

If 60 ml of ethanol is diluted to a final volume of 400 ml, you create a 35 % ethanol solution.

First, realize that you creating a solution with that contains a polar solute (ethanol) with a polar solvent (water). Remember that "like dissolves like."

If you pour 60 ml of ethanol in a volumetric flask, you add 340 ml of water to dilute this solution to a final volume of 400 ml.

Volumetric flasks are designed to make or dilute solutions to specified final volume.

Since you have 60 ml of ethanol in a total solution of 400 ml, the percentage of ethanol is 35 %.

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3 0
3 years ago
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3 years ago
Calcium has a cubic closest packed structure (fcc) as a solid. Assuming that calcium has an atomic radius of 197 pm, calculate t
Paha777 [63]

Answer:

1.536 g/cm^3 is the density of solid calcium.

Explanation:

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

We have:

r = 197 pm = 197\times 10^{-12} m = 197\times 10^{-12}\times 100 cm

r=197\times 10^{-10} m

a=r\times 2\sqrt{2}

a=197\times 10^{-10} m\times 2\sqrt{2}=557.200\times 10^{-10} cm

M = 40 g/mol

Z = 4

On substituting all the given values , we will get the value of 'a'.

\rho =\frac{4\times 40 g/mol}{6.022\times 10^{23} mol^{-1}\times (557.200\times 10^{-10} cm)^{3}}

\rho =1.536 g/cm^3

1.536 g/cm^3 is the density of solid calcium.

5 0
3 years ago
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