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lys-0071 [83]
3 years ago
15

Classify the following as fluids or solids: warm butter, liquid nitrogen, paper, neon gas, ice.

Chemistry
1 answer:
gogolik [260]3 years ago
6 0
Warm butter- liquid
Liquid nitrogen- gas
paper- solid
neon gas- gas
ice- solid
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Determine the mass of oxygen necessary to react with 2.3 moles of HCl
Orlov [11]
4HCl + O₂  →  2Cl₂  +  2H₂O

mole ratio of HCl  :  O₂  is   4  :  1

∴ if moles of HCl = 2.3 mol

then mol of O₂ =  2.3 mol  ÷  4
                        = 0.575 mol

mass of O₂  =  moles of O₂ × molar mass of O₂
                    =  0.575 mol ×  (16 × 2) g/mol
                    =  18.4 g
5 0
3 years ago
There are large spaces between gas molecules due to their weak
Eddi Din [679]

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Explanation:

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Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

5 0
3 years ago
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50 POINTS: PLEASE ANSWER AS QUICK AS POSSIBLE!
Dvinal [7]

Explanation:

The lack of a control group

6 0
3 years ago
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Select the compound that is most likely to increase the solubility of ZnSe when added to water.NaCnMgBr2NaClKClO4
vlada-n [284]

Answer:

NaCl.

Explanation:

In the solution, ZnSe ionizes to Zn^2^+ and Se^2^- . Following reaction represents the ionization of ZnSe in solution -

ZnSe ⇄ Zn^2^+ + Se^2^-

As we want to increase the solubility of ZnSe, we must decrease the concentration of dissociated ions so that the reaction continues to forward direction.

If we add NaCl to this solution, then we have Na^+ and Cl^- in the solution which will be formed by the ionization of NaCl.

Now, Zn^2^+ in the solution will react with two Cl^- ions to form ZnCl_2 as follows -

Zn^2^++2Cl^- ⇄ ZnCl_2

Due to this reaction the concentration of Zn^2^+ will decrease in the solution and more ZnSe can be soluble in the solution.

6 0
3 years ago
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