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lys-0071 [83]
3 years ago
15

Classify the following as fluids or solids: warm butter, liquid nitrogen, paper, neon gas, ice.

Chemistry
1 answer:
gogolik [260]3 years ago
6 0
Warm butter- liquid
Liquid nitrogen- gas
paper- solid
neon gas- gas
ice- solid
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Determine Δngas for each of the following reaction:(b) 2PbO(s) + O₂(g) ⇄ 2PbO₂(s)
Elis [28]

2PbO(s) + O₂(g) ⇄ 2PbO₂(s)

Then Δngas = -1

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about Equilibrium

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5 0
1 year ago
How many totals atoms are present in the compound : Mg(OH)2<br><br> A. 3<br> B. 4<br> C. 5<br> D. 7
Semenov [28]

1 atom Mg, 2 atoms O and 2 atoms H.

1 + 2 + 2 = 5, so correct answer is C

5 0
2 years ago
Plato answers . Which field will she use
Ira Lisetskai [31]

Answer:

A. biology

Explanation:

biology is the human body

6 0
3 years ago
Read 2 more answers
To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?
Cerrena [4.2K]

Answer:

V_{concentrated}=0.042L=4.2mL

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL

Best regards.

6 0
3 years ago
How many moles of compound are there in the following?
slavikrds [6]

a) (NH4)2SO4 --- 1 mole of it contains 2 moles of N, 8 moles of H, 1 mole of S, and 4 moles of O.

MM = (2 moles N x 14.0 g/mole) + (8 moles H x 1.01 g/mole) + (1 mole S x 32.1 g/mole) + (4 moles O x 16.0 g/mole) = 132 g/mole.

6.60 g (NH4)2SO4 x (1 mole (NH4)2SO4 / 132 g (NH4)2SO4) = 0.0500 moles (NH4)2SO4

b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.

4.5 kg Ca(OH)2 x (1000 g / 1 kg) x (1 mole Ca(OH)2 / 74.0 g Ca(OH)2) = 60.8 moles Ca(OH)2

8 0
3 years ago
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