Okay so 3x-6(1/2x+4)=-12. 3x-3x-24=-12. x-24=-12.x=-36
It's 3/4 because (y2-y1)/(x2-x1)
The image is missing, so i have attached it
Answer:
Equation is;
q/sin 105 = 15/sin 30
Step-by-step explanation:
We are given;
Angle Q = 105°
Angle S = 30°
s = 15
From sine rule we know that;
a/sin A = b/sin B = c/sin C.
Thus, applying that to this question, we can find side q.
Thus;. q/Sin Q = s/Sin S
Plugging in the relevant values to obtain ;
q/sin 105 = 15/sin 30
The straight line distance from the helicopter to the accident is the hypotenuse of the right triangle when we connect all the three points. Solving for the horizontal distance, we make use of the equation,
sin 18 = 1560 ft / horizontal distance
Solving the equation above, the horizontal distance is 5048.27 ft.
Answer: See explanation
Step-by-step explanation:
From the information given, the following can be deduced:
Let rate of jet in still air be J
Let rate of wind be W
The formula for distance:
d = rt
Therefore, r = d/t
When, flying against the wind, then the Jet flies at a rate of J - W which will be:
= 1590mi/3hrs
= 530mph
When flying with the wind the jet will fly at a rate of J+W which will be:
= 8240mi/8hrs
= 1030 mph
Their average rate will be:
J = (530+1030)/2
= 1560/2
J = 780 mph
Since J - W = 530
Therefore, so
780 - W = 530
W = 780 - 530
W = 250 mph
The Jet in still air flies at a rate of 780 mph and the wind speed is 250 mph