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guapka [62]
4 years ago
8

As a part of their weather unit, Anoki’s science class took a hot air balloon ride. As they passed over a fenced field, the angl

e of depression of the closer side of the fence was 32°, and the angle of depression of the farther side of the fence was 27°. If the height of the balloon was 800 feet, estimate the width of the field. Round your answer to the nearest foot. 2016_01_25_17_23_501.png The width of the field is about feet

Mathematics
1 answer:
yulyashka [42]4 years ago
7 0
Please refer to the figure attached for the diagram of this problem.

Steps needed to find the width of the field (CD):

First, we should note that angle d would be equal to 27 degrees because there are two parallel lines that are cut by a transversal. Furthermore, angle a would be equal to 5 degrees since we just need to subtract 27 from 32.

We then subtract 27 and 5 from 180 to get angle c. 180-27-5=148. Angle c is therefore 148 degrees.

Next, we need to find angle e which is just the supplementary of angle c. Angle e therefore measures 180-148=32 degrees.

For the next step we use sine law to find the length of segment AC:
\frac{sin(32)}{800} = \frac{sin(90)}{AC}
AC=1509.66

Lastly, we need to utilize the sine law again to find the length of segment CD or the width of the field:
\frac{sin(27)}{1509.66} = \frac{sin(5)}{CD}
CD=290

ANSWER: The width of the field is 290 ft.

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Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

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3 years ago
Pleaseeeee helppppp meee​
Genrish500 [490]
The answer is one half
7 0
3 years ago
''A florist measures the lengths of roses. The lengths in inches of a dozen roses are given below'' I'm really confused.
alexira [117]

Complete data:

13.5 13.5 13.25 13.0 13.25 13.5 13.0 13.25 13.0 13.25 12.75 12.75 Part A How many dots should go above each data value in the line plot? Type a number in each box

Answer:

12.75 ___ 2 dots

13.0 ____ 3 dots

13.25 ___ 4 dots

13.5 ___ 3 dots

Step-by-step explanation:

Given the data :

13.5 13.5 13.25 13.0 13.25 13.5 13.0 13.25 13.0 13.25 12.75 12.75

To know the Number of dots for each data value, we obtain the frequency of each data value ;

Length of Rose____ Frequency

12.75 _________:__ 2

13.0 ____________ 3

13.25 ___________ 4

13.5 ____________ 3

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3 years ago
Compare the initial values and the rates of change for Jenna's and Finn's plans. What do they mean in the problem situations? ​
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Answer:

Step-by-step explanation:

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3 years ago
Suppose in this semester, our Exam 1 average was about 86 with an SD of about 10. Suppose the correlation between our Exam 1 and
Oduvanchick [21]

Answer:

the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

Step-by-step explanation:

Given the data in the question;  

mean X" = 86

SD σx = 10

Y" = 76

SD σy = 8.2

r = 0.6

Here, Exam 2 is dependent and Exam 1 is independent.

The Regression equation is

y - Y" = r × σy/σx  ( x - x" )

we substitute

y - 76 = 0.6 × 8.2/10  ( x - 86 )

y  - 76 = 0.492( x - 86 )

y  - 76 = 0.492x - 42.312

y = 0.492x - 42.312 + 76

y = 0.492x + 33.688

Hence, the slope of the regression equation for predicting our Exam 2 scores from Exam 1 scores is 0.492

And the y-intercept of the regression equation for predicting our Exam 2 scores from Exam 1 is 33.688

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