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Verizon [17]
3 years ago
11

If the area of an ice rink is 404 square yards, what is the perimeter of the rink?

Mathematics
1 answer:
mezya [45]3 years ago
4 0
404 divided by 2 equals 201.

2 + 2 + 201 + 201 = 406 is the perimeter

Please click the happy face button! :)
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3 x A = 30 + 30<br><br> it’s a 3rd grade problem but don’t know the answer
xenn [34]

Answer: A=20

Step-by-step explanation:

3×A=30+30............eqn 1

3A=60

A=60/3

A=20

Substitute A=20 into equation 1

3x20= 30+30

8 0
3 years ago
HI CAN I GET SOMEONE TO HELP ME WITH MATH IM FAILING TY! :)
oksano4ka [1.4K]

Answer:

20 square meters

Step-by-step explanation:

area = length x width

area of grass = 4 x 4 = 16

area of grass and cement = 6 x 6 = 36

<em>Now you subtract to find the area of the cement.</em>

36 - 16 = 20

3 0
3 years ago
The solution to the system -2x+5y=-15 and 5x+2y=-6 is what
cupoosta [38]

Step-by-step explanation:

−2x+5y=−15 and 5x+2y=−6

Rewrite equations:

−2x+5y=−15;5x+2y=−6

Step: Solve−2x+5y=−15for x:

−2x+5y=−15

−2x+5y+−5y=−15+−5y(Add -5y to both sides)

−2x=−5y−15

−2x−2=−5y−15−2(Divide both sides by -2)

x=52y+152

Step: Substitute52y+152forxin5x+2y=−6:

5x+2y=−6

5(52y+152)+2y=−6

292y+752=−6(Simplify both sides of the equation)

292y+752+−752=−6+−752(Add (-75)/2 to both sides)

292y=−872

292y292=−872292(Divide both sides by 29/2)

y=−3

Step: Substitute−3foryinx=52y+152:

x=52y+152

x=52(−3)+152

x=0(Simplify both sides of the equation)

Answer:

x=0 and y=−3

8 0
3 years ago
Finals are​ over, and you are moving back home for the summer. You need to rent a truck to move your possessions from the colleg
rewona [7]
In short you just multiply 0.480.48 by the amount of miles you drive add that to 24.9024.90 and you get you total
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5 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
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