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Zanzabum
3 years ago
11

In your top dresser drawer there are 6 blue socks and 10 grey socks, unpaired and mixed up. one dark morning you pull two socks

from the drawer (without replacement, of course!). what is the probability that the two socks match?
Mathematics
1 answer:
Troyanec [42]3 years ago
3 0
The probability that the two socks match can be translated into the probability of getting two blue socks or two grey socks.
The combination ways for taking 2 socks from 16 socks would be: 16C2= 16!/2!14!= 120
Way to get 2 blue socks of 6 blue sock: 6C2= 6!/2!4!= 15
Way to get 2 grey socks of 10 grey sock: 10C2= 10!/2!8!= 45

Then the probability is: 15+45/ 120= 60/120= 1/2 
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3 years ago
Find all solutions for a triangle with a = 14, b= 12, and B = 90°.
ziro4ka [17]

Answer:

No solution.

Step-by-step explanation:

Given

a = 14; b= 12; B = 90^\circ

Required

Find all possible solutions

If B = 90^\circ, then the triangle is right-angled and the hypotenuse is at b

Given that a = 14; b= 12;

This implies that a > b

In a right-angled triangle, the hypotenuse (side b) is the longest.

Since this is not true for the given sides, then the triangle has no solution.

5 0
3 years ago
Helpp me pls I'm struggling
Ierofanga [76]

Answer:

B. 2nd Play and B. 2nd Play

Step-by-step explanation:

#1) Going negative means going backwards.

-8<10.5

#2) Absolute value means making all numbers INSIDE the two lines positive.

I-8I = 8

I10.5I = 10.5

3 0
2 years ago
Read 2 more answers
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

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3 years ago
What is 5-2+(9÷1)×9+0
Anna [14]
The answer is 84 because of process priority
6 0
3 years ago
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