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3 years ago

Simplify: x2/6 ⋅ x2/4

Mathematics

1 answer:

Elden [556K]3 years ago

8 0

Answer:

x ^2/ 6

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Maeve surveys a large number of students at the bowling alley about their favorite weekend activity. The table below shows the r

ArbitrLikvidat [17]

The answer would be c because she only surveyed at the bowling alley instead of different places

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3 years ago

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i need the answer no playing around please and if the answer is right i will give you a thanks and full stars pleaseeeee

MrRa [10]

Answer:

50+50x

Step-by-step explanation:

they're asking you to use distributive property

so what you have to do is multiply everything that is in the parenthesis by 10

5x10=50

5x10x=50x

so the answer is 50+50x

have a great day :D

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3 years ago

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The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸

Lorico [155]

Answer:

The Width of the Rectangle = $10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$ . Therefore their greatest monomial factor = $10y^6$

The Width of the Rectangle = $10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

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3 years ago

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Work out (5.32 x 10^-7): (2.5 x 10^-5)<br>Give your answer in standard form

Mrrafil [7]

Answer:

1.33×10^-6

Step-by-step explanation:

5.32 x 10^-7= 5.32×10^(-5-2)= 5.32×10^-2×10^(-5)

=0.0532×10^-5

(0.0532×10^-5) (2.5 x 10^-5)

0.0532×2.5 × 10^-5

0.133×10^-5= 1.33×10^-1 ×10^-5

1.33×10^-6

8 0

2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

3 years ago