.4r when r=6<br> someone help

PLEASE HELP ANYONE WOULD HELP ME PASSS

Lana71 [14]

1. 5/11
2. 11
3. 2

These are all just properties of logarithms.

4 0

3 years ago

Solve for u.<br> U/-1 +-4=-1<br> U =

kherson [118]

Answer:

U = -3

Step-by-step explanation:

U/-1 +-4=-1

Add 4 to each side

U/-1 +-4+4=-1+4

U / -1 = 3

Multiply each side by -1

U / -1 * -1 = 3* -1

U = -3

3 0

3 years ago

Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 7.0% per year.

fredd [130]

Answer:

The number of years it would take is $n = 2 \ years$

Step-by-step explanation:

From the question we are told that

The earning per share is $P =$ $3.50

The growth rate is r = 7.0%

The duration is $t = 5 \ years$

Generally the future value is mathematically represented as

$A = P(1 + \frac{r}{100} )^n$

Where P is the present value

n is the time period

A is the future value which is mathematically evaluated as

$A = 3 * P$

substituting value

$A = 3 * 3.50$

$A =$ $ 10.5 0

So

$A = P(1 + \frac{r}{100} )^n$

$10.5 = 3.5(1 + \frac{7}{100} )^n$

$10.5 = 3.225^n$

Taking log of both sides

$log 10.5 = nlog 3.225$

$1.0212 = n(0.5085)$

$n = \frac{1.0212}{(0.5085)}$

$n = 2 \ years$

4 0

3 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in t

andreyandreev [35.5K]

Answer:

The test statistic is c. 2.00

The p-value is a. 0.0456

At the 5% level, you b. reject the null hypothesis

Step-by-step explanation:

We want to test to determine whether or not the mean waiting time of all customers is significantly different than 3 minutes.

This means that the mean and the alternate hypothesis are:

Null: $H_{0} = 3$

Alternate: $H_{a} = 3$

The test-statistic is given by:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

Sample of 100 customers.

This means that $n = 100$

3 tested at the null hypothesis

This means that $\mu = 3$

The average length of time it took the customers in the sample to check out was 3.1 minutes.

This means that $X = 3.1$

The population standard deviation is known at 0.5 minutes.

This means that $\sigma = 0.5$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3.1 - 3}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is z = 2.

The p-value is

Mean different than 3, so the pvalue is 2 multiplied by 1 subtracted by the pvalue of Z when z = 2.

z = 2 has a pvalue of 0.9772

2*(1 - 0.9772) = 2*0.0228 = 0.0456

At the 5% level

0.0456 < 0.05, which means that the null hypothesis is rejected.

7 0

3 years ago

1. A notebook costs $5 more than a folder. Greg purchased 3 notebooks and 2 folders and paid a total cost $30. What is the cost

stiv31 [10]

Answer
Notebook each =$4
Folder each = $9

First we write out what we know
Notebook = n
Folder = f
It says a notebook is +5 than a folder so
f = n +5
It says he bought 3 notebooks and 2 folders for $30
3n + 2f = 30

Because we know from the first equation
f=n+5, we can substitute that into the second equation for f

3n + 2(n+5) = 30
3n + 2n +10 =30. Now Combine like terms
5n +10 =30. Now isolate n by subtracting 10 from both sides
5n = 20. Now isolate n by dividing both sides by 5
n = 4

Now we do the same thing to find f
We substitute the value of n (4) into the equation 3n + 2f =30
3(4) +2f =30
12 +2f =30. Now isolate f by subtracting 12 from both sides
2f = 18. Now isolate f by dividing both sides by 2
f = 9

We check our work by inserting the n and f values we found into one of the equations
n + 5 = f
4 + 5 = 9
9 = 9. It worked it equals so it’s correct

8 0

1 year ago

.4r when r=6 someone help