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Hoochie [10]
3 years ago
13

Which of the lists of letters all have rotational symmetry?

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

N, O, S, Z, which will be B

Step-by-step explanation:

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The circle is inscribed in Triangle AEC. Which are congruent line segments
Harlamova29_29 [7]

Answer:

E-F and E-D

C-B and C-D

Step-by-step explanation:

The circle and triangle are as shown.  The options are:

  • A-B and C-B
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  • E-D and C-D
  • A-F and E-F
  • C-B and C-D

By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites.  Therefore, only segments that are legs of the same kite are congruent.  So the answer must be E-F and E-D, and C-B and C-D.

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3 years ago
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How would I solve this equation?
Assoli18 [71]
2(7/2)^x = 49/2

Divide both sides by 2:

(7/2)^x = 49/4

I notice that 49/4 can be rewritten as (7/2)^2, so we now have:

(7/2)^x = (7/2)^2

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Plz help!!<br> Consider the given right triangle.
aalyn [17]

Answer:

b = 8

c = 16

Step-by-step explanation:

From the given right triangle,

a = 8\sqrt{3}, m(∠B) = 30°

By applying sine rule in the given triangle,

cos(B) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(B) = \frac{BC}{AB}

cos(30°) = \frac{8\sqrt{3}}{c}

\frac{\sqrt{3} }{2}= \frac{8\sqrt{3} }{c}

c = 16

Further we apply tangent rule,

tan(B) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(30°) = \frac{b}{a}

\frac{1}{\sqrt{3}}=\frac{b}{8\sqrt{3} }

b = 8

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