Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
Answer: 7x^2 + 2x + 7
Step-by-step explanation:
Combine likes terms that have alike variables and alike exponents.
(3x^2 + 4x^2) + (2x) + (2 + 5)
7x^2 + 2x + 7
If the legs are length a and b and hyptonuse is c then
a²+b²=c²
so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x
Answer:
(a) 3 ft, 4 ft, 5 ft
Step-by-step explanation:
The triangle inequality requires the sum of the two short sides exceed the long side.
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a) 3 ft + 4 ft = 7 ft > 5 ft . . . . . triangle is possible
b) 4 yd + 1 2/3 yd = 5 2/3 yd < 10 yd . . . . not a possible triangle
c) 3 ft + 3 ft = 6 ft < 7 ft . . . . not a possible triangle
d) 4 in + 4 in = 8 in . . . . not a possible triangle (not greater than 8 in)
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The first set of side lengths can form a triangle: 3 ft, 4 ft, 5 ft.
Given:
Consider the below figure attached with this question.
To find:
The perimeter of the polygon UVWXYZ.
Solution:
All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.
From the figure it is clear that,
UV = 9 units
VW = 2 units
WX = 3 units
XY = 3 units
YZ = 6 units
ZU = 5 units
Now, perimeter is the sum of all the sides.
Therefore, the perimeter of UVWXYZ is 28 units.
