Thanks if the answer is right

Juliette [100K]

X=-3 because first substitute the value of y into the original equation -2x-3=x+6 then isolate the variables -2x-x=6+3 which is -3x=9 then we can divide x=9/-3 which =-3

3 0

3 years ago

Read 2 more answers

The results of the math exam showed that three eighths of the students made an “A” and one third of them made a “B”. In total, h

grigory [225]

Answer:

b the answer is b

Step-by-step explanation:

idk what they mean but i got an 100 and i had this questin so a

3 0

3 years ago

HELP! ANSWER THE QUESTION IN THE PICTURE BELOW. THANK YOU!!!!!!!!

max2010maxim [7]

The last one would be negative.

Positive times positive = positive

Positive times negative = negative

Negative times negative = positive

So basically, if there is an odd number of negatives, then it'll end up negative, with some exceptions.

So now we know it has to either be the first one or the last one.

The first one is multiplied by 0, so it can't be that one.

So it has to be the last one.

7 0

3 years ago

how do you solve for a in : a/9 = -4 ? I would really appreciate it if you guys could explain how you got the answer

tigry1 [53]

Look at it step by step guys:a\9=-4 so u just cross in top and bottom that will be -36=a ,or a=-36.....

4 0

3 years ago

preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha

VladimirAG [237]

Answer:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

n=369

Step-by-step explanation:

1) Notation and definitions

$X=40$ number of the selected labourers opt for a new incentive scheme.

$n=100$ random sample taken

$\hat p=\frac{40}{100}=0.4$ estimated proportion of the selected labourers opt for a new incentive scheme.

$p$ true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: